Answer:
You will need to implement a for loop ( I am assuming this is java)
Explanation:
int count20s = 0;
for(int x =0; x< customerAges.length;x++){
if(20 <= customerAges[x] && customerAges[x] <= 29){
count20s++;
}
Answer:
Answer: C Scrum
Explanation:
Answer: C Scrum would BEST support this objective, to collect and evaluate user stories related to the organization’s internally designed CRM tool.
Answer:
Explanation:
bool isPalindrome(string str)
{
int length = str.length();
for (int i = 0; i < length / 2; i++) {
if (str [i] != str [length – 1 – i]) {
return false;
}
}
cout << str << "is a palindrome";
return true;
}
Answer:
Explanation:
Generally speaking, there are two kinds of tags - opening tags: <html> and closing tags: </html>. The only difference between an opening tag and a closing tag is the forward slash "/". You label content by putting it between an opening tag and a closing tag.
HTML is all about elements.
Answer:
negatives = []
zeros = []
positives = []
while True:
number = input("Enter a number: ")
if number == "":
break
else:
number = int(number)
if number < 0:
negatives.append(number)
elif number == 0:
zeros.append(number)
else:
positives.append(number)
for n in negatives:
print(n)
for z in zeros:
print(z)
for p in positives:
print(p)
Explanation:
Initialize three lists to hold the numbers
Create a while loop that iterates until the user enters a blank line
Inside the loop:
If the number is smaller than 0, put it in the negatives list
If the number is 0, put it in the zeros list
Otherwise, put the number in the negatives list
When the while loop is done, create three for loops to print the numbers inside the lists
