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3 years ago

Devide . Reduce the answer to the lowest terms 3/4 ÷1/3

Mathematics

1 answer:

Vitek1552 [10]3 years ago

6 0

3/4 = .75 and 1/3 = .333 repeated .75/.3333 = 2.25 or 2 1/4

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rodikova [14]

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3 years ago

Write simplified expressions for the area and perimeter of the rectangle.

mel-nik [20]

Answer:

Area = 12x + 66

Perimeter = 2x + 35

Step-by-step explanation:

Area= 12(5.5 + x)

= 12x + 66

Perimeter = 2[(5.5 + x)+12]

= 2(17.5 + x)

= 2x + 35

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3 years ago

Find an equation for the line perpendicular to y=−15x+3 with x-intercept at x = 3.

Alex Ar [27]

bearing in mind that perpendicular lines have negative reciprocal slopes, let's find the slope of the provided line then

$\bf y=\stackrel{\stackrel{m}{\downarrow }}{-15}x+3\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-15\implies -\cfrac{15}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{1}{15}}\qquad \stackrel{negative~reciprocal}{+\cfrac{1}{15}\implies \cfrac{1}{15}}}$

well, we know the x-intercept is at x = 3, recall when a graph intercepts the x-axis y = 0, so this point is (3 , 0). Then we're really looking for the equation of a line whose slope is 1/5 and runs through (3 , 0).

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{0})~\hspace{10em} slope = m\implies \cfrac{1}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=\cfrac{1}{5}(x-3)\implies y=\cfrac{1}{5}x-\cfrac{3}{5}$

6 0

4 years ago

What is the solution of the system?

Dmitry_Shevchenko [17]

We have $\begin{bmatrix}2x+y=20\\ 6x-5y=12\end{bmatrix}$

$\mathrm{Multiply\:}2x+y=20\mathrm{\:by\:}3:\ 6x+3y=60$

$\begin{bmatrix}6x+3y=60\\ 6x-5y=12\end{bmatrix}$

6x - 5y = 12
-
6x + 3y = 60
/
-8y = -48

$-8y=-48 \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}-8 \ \textgreater \ \frac{-8y}{-8}=\frac{-48}{-8} \ \textgreater \ y=6$

$\mathrm{For\:}6x+3y=60\mathrm{\:plug\:in\:}\ \:y=6$

$6x+3\cdot \:6=60 \ \textgreater \ \mathrm{Multiply\:the\:numbers:}\:3\cdot \:6=18 \ \textgreater \ 6x+18=60$

$\mathrm{Subtract\:}18\mathrm{\:from\:both\:sides} \ \textgreater \ 6x+18-18=60-18 \ \textgreater \ 6x=42$

$\mathrm{Divide\:both\:sides\:by\:}6 \ \textgreater \ \frac{6x}{6}=\frac{42}{6} \ \textgreater \ x = 7$

Therefore....
$The\:solutions\:to\:the\:system\:of\:equationts\:are \ \textgreater \ y=6,\:x=7$

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4 years ago

This is where you can use your pickup lines without getting in trouble

Afina-wow [57]

Answer:

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Step-by-step explanation:

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3 years ago