All categories

3 years ago

What is the volume of the sphere below?

Mathematics

2 answers:

WINSTONCH [101]3 years ago

5 0

Answer:

The correct option is C.

Step-by-step explanation:

The radius of the sphere is 5 units.

The volume of a sphere is

$V=\frac{4}{3}\pi r^3$

Where, r is radius of the sphere.

$V=\frac{4}{3}\pi (5)^3$

$V=\frac{4}{3}\pi (125)$

$V=\frac{500}{3}\pi$

The volume sphere is $\frac{500}{3}\pi$ .

Therefore correct option is C.

jek_recluse [69]3 years ago

3 0

Volume = (4/3) * pi * 5^3

= 500 pi / 3

C

You might be interested in

mrs carter teaches a total of 80 students. of the students that she teaches, 30% will go on a field trip to the art museum along

castortr0y [4]

32 ^^ I really hope this is right and helps xD

8 0

3 years ago

Read 2 more answers

The diameter of a circle is 23 inches and the circle has two chords of length 14 inches what is the distance from each chord to

Svetradugi [14.3K]

Answer:

9.12 + 9.12 = 18.24 inches

Step-by-step explanation:

Diameter = 23 inches (given)

Radius = 11.5 inches

2 Chords of length = 14 inches ( You didn't specify if the 14 inches is for both chords or for a single cord. I'll assume it's for two cords 14 and 14inches apart.

To clearly solve this, we'll make some mild assumptions.

Let the perpendicular distance of the chords from the center of the circle to represented as " x and y"

Therefore:

x^2 + 7^2 = 11.5 ^ 2

x^2 + 49 = 132.25

x^2 = 132.25 - 49

x^2 = 83.25

x = √ 83.25

x = 9.12 inches

Since the cords have thesame length (Assumed from the way the question was structured, the distance would still be thesame)

y^2 + 7^2 = 11.5 ^ 2

y^2 + 49 = 132.25

y^2 = 132.25 - 49

y^2 = 83.25

y = √ 83.25

y = 9.12 inches

Therefore, the distance will be :

9.12 + 9.12 = 18.24 inches

Have fun!

6 0

4 years ago

Carlos buys a new bicycle

Bond [772]

16% of 231 is 36.80
16% + 84% = 100%
36.80+ 231 = $267.80
Ans = $267.80

3 0

3 years ago

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side$

4 0

3 years ago

4' 9''+ 7''<br> the sum pleaseee

joja [24]

Answer:

5'4" or 64 inches

Step-by-step explanation:

5 0

3 years ago