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3 years ago

3/11 divided by 2/9 equals what

Mathematics

2 answers:

KonstantinChe [14]3 years ago

7 0

Answer: 1 and 5/22

Step-by-step explanation: In this problem, we have 3/11 divided by 2/9. Dividing by a fraction is the same as multiplying by its reciprocal. In other words, we can change the division sign to multiplication and flip the second fraction.

So, 3/11 ÷ 2/9 can be rewritten as 3/11 × 9/2.

Now, we are simply multiplying fractions. To multiply fractions, we multiply across the numerators and multiply across the denominators.

$(\frac{3}{11}) (\frac{9}{2}) = \frac{27}{22}$

The fraction 27/22 can be written as a mixed number by dividing the denominator into the numerator.

Image provided.

Therefore, 3/11 divided by 2/9 = 1 and 5/22.

Grace [21]3 years ago

6 0

Answer:

When dividing fraction, it's always a good idea to use the copy-dot-flip method, or copy-dot-reciprocal.

So in this example it would be

3/11 * 9/2 = 1.227 or 1.22

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Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 6, \sigma = 0.2$

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6-6}{0.2}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

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(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X 5.8.

X = 6.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

X = 5.8

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587

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This is 1 subtracted by the pvalue of Z when X = 5.7.

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This is 1 subtracted by the pvalue of Z when X = 5.

$Z = \frac{X - \mu}{\sigma}$

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Answer:

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tatiyna

To solve this problem, let us first assign some variables. Let us say that:

x = pigs

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Answer:

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Pro por tions:

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