Update the question so it's on-topic for Mathematics Stack Exchange. Closed 4 years ago. How many words can be made by using the letters of the word ENGLAND such that words begin and end with a vowel? I couldn't understand how come the answer to this question is 120
The answer to the second one is 243/2 but I'm not 100% positive
Answer:
C.
discrete data
Step-by-step explanation:
The given function is:
C(p) = 0.95p
Where p represents the number of bolts purchased. We can calculate the cost based on the number of bolts purchased.
An important distinction between discrete and continuous data is that the continuous data is measured while discrete data is calculated or counted. Since we are obtaining the data by calculation, it must be discrete data.
The function can take on only specific values. For example for p=0, C is 0 and for p=1 the value of C is 0.95. The function cannot take any value in between 0 and 0.95. This is a characteristic of discrete function. A continuous function can take all possible values in an interval.
Therefore, the answer to this question is: The Function models discrete data.
Answer:
mean
Step-by-step explanation:
Answer:
exactly one, 0's, triangular matrix, product and 1.
Step-by-step explanation:
So, let us first fill in the gap in the question below. Note that the capitalized words are the words to be filled in the gap and the ones in brackets too.
"An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with EXACTLY ONE of the (0's) replaced with some number k. This means it is TRIANGULAR MATRIX, and so its determinant is the PRODUCT of its diagonal entries. Thus, the determinant of an elementary scaling matrix with k on the diagonal is (1).
Here, one of the zeros in the identity matrix will surely be replaced by one. That is to say, the determinants = 1 × 1 × 1 => 1. Thus, it is a a triangular matrix.
