Can someone please answer this???? ASAP

Mathematics

1 answer:

timofeeve [1]3 years ago

7 0

Answer:

A. $y=-\dfrac{8}{7}x-\dfrac{18}{7}$

Step-by-step explanation:

Let $y=mx+b$ be the equation of the perpendicular line.

Two perpendicular lines have slopes with product equal to -1. The slope of the given line is $\frac{7}{8}$ Hence,

$\dfrac{7}{8}\cdot m=-1\\ \\m=-\dfrac{8}{7}$

is the slope of needed line.

This line passes through the point (-4,2), so its coordinates satisfy the equation:

$2=-\dfrac{8}{7}\cdot (-4)+b\\ \\b=2-\dfrac{32}{7}=-\dfrac{18}{7}$

Therefore, the equation of the line is

$y=-\dfrac{8}{7}x-\dfrac{18}{7}$

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Matt can walk 500 m from his home on King Street, and then 900m along Queen Street to go to his school. He can also walk across

brilliants [131]

Answer:

He walks 1030 meters if he walks across the park.

Step-by-step explanation:

In order to solve this question we will need to know that $c^{2} = a^{2} + b^{2}$ (were c is the length of the hypotenuse (the diagonal line) of a right angle triangle, and a and b are the legs (the sides that form a right angle). So them means that.....

Let "c" be the distance he will need to walk if he was going to go through the park

Let "a" be the distance he walks on King Street

Let "b " be the distance he walks on Queen Street, then.....

$c^{2} = a^{2} + b^{2}$

$c = \sqrt{a^{2} + b^{2} }$

(Now plug in the values of a and b and get.....)

c = $\sqrt{500^{2} + 900^{2} }$

c = $\sqrt{1060000 }$

c = 1029.563014............

So I would assume that you have to round to the nearest meter. And as a result we get 1030 meter.

7 0

3 years ago

What is the slope and y-intercept of the line -x-7y=-56?

Vinvika [58]

Equation of line: Y= mX + c
where m is slope and c is y intercept.
rewrite equation to be,
-x-7y=-56
-7y=x-56
7y= -x +56
y = -1/7 x +8

slope = -1/7
y intercept = 8

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4 years ago

Help me with my math pls

kondaur [170]

$18 - ( \sqrt[3]{27} )^{3}$