Answer:
448 strings
Explanation:
Each bit string can be filled by two ways either 0 or 1. If the bit strings of length contain the substring '111000' we therefore need a substring of length 6.
The selection of bits starts from the 1st bit to 7th bit enclosing the substring 111000 and ensuring that the length 6 are all filled. So, there will be 7 ways to contain this substring.
The total ways to contain this substring = 7*2^6 =448
Therefore 448 strings of length 12 contain the substring '111000'.
Convert a fraction to a decimal value using the fraction to decimal calculator by entering your fraction below. Use the “/” symbol for the fraction bar. To convert a decimal to a fraction, use our decimal to fraction calculator. Check out our fraction to percent calculator to convert fractions to a percentage.
Answer:
Hypertext is a text in a document which references some other link within the same page or another page.
Search engine is an information retrieval system from larger pool of resources.
IT is for information technology whereby with the help of systems and communication medium we are able to send, retrieve information from one place to another.
Explanation:
Some website page can contain hypertext which is a link to another page. These are simple text upon clicking it lands us to another page or a pop up activity.
Examples of search engine is google with which we can search and retrieve information from a large database servers.
IT governs the ways these information exchanges taking place between client and sender with help of systems(computers) and communicating medium(internet).
Answer:
def remove_duplicates(lst):
no_duplicate = []
dup = []
for x in lst:
if x not in no_duplicate:
no_duplicate.append(x)
else:
dup.append(x)
for y in dup:
if y in no_duplicate:
no_duplicate.remove(y)
return no_duplicate
Explanation:
Create a function called remove_duplicates that takes one parameter, lst
Create two lists one for no duplicate elements and one for duplicate elements
Create for loop that iterates through the lst. If an element is reached for first time, put it to the no_duplicate. If it is reached more than once, put it to the dup.
When the first loop is done, create another for loop that iterates through the dup. If one element in no_duplicate is in the dup, that means it is a duplicate, remove that element from the no_duplicate.
When the second loop is done, return the no_duplicate
<span>be clearly marked as distinct from variables. Instead, they should be marked or labeled otherwise, and an explicit indication that they are not variables should be provided both next to the structure and class names, and also on a separate visual material.</span>
