We have the following function:
y = 2x ^ 2 - 12x - 32
We match zero:
2x ^ 2 - 12x - 32 = 0
We rewrite the function:
x ^ 2 - 6x - 16 = 0
(x-8) * (x + 2) = 0
The zeros of the function are:
x1 = 8
x2 = -2
Where,
8> -2
Thus,
d = 8
e = -2
Then, to find the minimum function we derive:
y '= 4x - 12
We equal zero and clear x:
4x-12 = 0
x = 12/4
x = 3
Therefore, the value of f is:
f = 3
Answer:
The values of d, e, and f are:
d = 8
e = -2
f = 3
Answer:
1) -2>-5
2) -2
3) A or C
Step-by-step explanation:
Hello!
First of all, let's undo the square roots by squaring both sides.
6x+2=9x-8
We subtract 9x from both sides.
-3x+2=-8
We subtract 2 from both sides.
-3x= -10
We divide both sides by -3.
x=10/3
I hope this helps!
Answer:
$6.34
Step-by-step explanation:
15.86 / 2.5 = 6.34
$6.34
Answer:
The answer is -- all integers from 10 to 50, inclusive
Hope I Helped.
(I am sure of the answer, I have completed the test.)