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Anna35 [415]
3 years ago
14

What is the domain of the function in this table?​

Mathematics
1 answer:
Talja [164]3 years ago
6 0

Answer:

there is no table appearing so unfortunately no one can answer this for you. sorry!!

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Emily wants to put trim around a square window and measures 3 ft on each side. How many feet of t r i m does she need?
Alexeev081 [22]

Answer:

12 feet

Step-by-step explanation:

3 times 4 is 12

you would multiply by 4 because of the 4 sides of the window

8 0
2 years ago
What is the volume of this figure?
katovenus [111]

Answer:

Volume = 480 cm³

Step-by-step explanation:

Volume = lwh

<em>*Split the shape into 3 rectangles.</em>

<u>Rectangle 1:</u> 4 x 4 x 8 = 128

<u>Rectangle 2:</u> 14 x 4 x 4 = 224

<u>Rectangle 3:</u> 4 x 4 x 8 = 128

<u>Total:</u> 128 + 224 + 128 = 480 cm³

6 0
3 years ago
Read 2 more answers
Can. Y’all help with this
solmaris [256]

Answer:

Your Answer Would be the 3rd Option.

Step-by-step explanation:

The Initial Value is : 4. All you have to do is look for when the x = 0

ROC: 1/2. Minutes =x, Inches= Y. To find ROC, take

Y2 - Y1

----------

X2 - Y1

Replacing those with numbers:

5 - 4

-------

2 - 0

Your ROC is 1/2 .

Equation:

y= 1/2x + 4

Know that The 4 is the initial value, so it's always in that spot. Your ROC is always Next to the x, which also means it's the slope.

7 0
3 years ago
Solve the given differential equation by using an appropriate substitution. The DE is a Bernoulli equation.
Mama L [17]

Multiplying both sides by y^2 gives

xy^2\dfrac{\mathrm dy}{\mathrm dx}+y^3=1

so that substituting v=y^3 and hence \frac{\mathrm dv}{\mathrm dv}=3y^2\frac{\mathrm dy}{\mathrm dx} gives the linear ODE,

\dfrac x3\dfrac{\mathrm dv}{\mathrm dx}+v=1

Now multiply both sides by 3x^2 to get

x^3\dfrac{\mathrm dv}{\mathrm dx}+3x^2v=3x^2

so that the left side condenses into the derivative of a product.

\dfrac{\mathrm d}{\mathrm dx}[x^3v]=3x^2

Integrate both sides, then solve for v, then for y:

x^3v=\displaystyle\int3x^2\,\mathrm dx

x^3v=x^3+C

v=1+\dfrac C{x^3}

y^3=1+\dfrac C{x^3}

\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}

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4 years ago
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