Answer, step-by-step explanation:
A. With the previous exercise we can deduce that there is the situation of a number of sales in a grocery store, the relative frequency for the number of units sold, is shown below:
units sold. relative frequency. Acumulative frequency. interval of random numbers
30. 0.16. 0.16. 0.00 <0.16
40. 0.24. 0.4. 0.16 <0.4
50. 0.3. 0.7. 0.4 <0.7
60. 0.2. 0.9. 0.7<09
70. 0.1. 1. 0.9<1
B. For the next point, they give us some random numbers and then it is compared with the simulation of 10 days in sales:
random Units
number. sold
0.12. 30
0.96. 70
0.53. 50
0.80. 60
0.95. 70
0.10. 30
0.40. 50
0.45. 50
0.77. 60
0.29. 40
the two lists are compared so that opposite each one is the result of the simulation
44
Step-by-step explanation:
let boys be x and girls be y
x/y=5/6
x=5y/6....(1)
if 6 boys join the club that will be x+6
Therefore:
(x+6)/y=13/12
13y=12x+72
13y-12x=72
Recall x=5y/6
Therefore:
13y-12(5y/6)=72
13y-(2*5y)=72
13y-10y=72
3y=72
y=24 people
Therefore:
x=(5*24)/6
x=20 people
Therefore people in the club before are 20+24=44
Answer:
At time t = 0.408 sec diver will be at maximum height
Step-by-step explanation:
We have given equation of the height 
We know that velocity is the rate of change of distance with respect to time
So 
At maximum height velocity will be zero
So 
t = 0.408 sec
So at time t = 0.408 sec diver will be at maximum height
Which method? There is the substitution method, elimination method, and comparison method
Here you go!! Hope it helps !!