Answer:
The steady state proportion for the U (uninvolved) fraction is 0.4.
Step-by-step explanation:
This can be modeled as a Markov chain, with two states:
U: uninvolved
M: matched
The transitions probability matrix is:

The steady state is that satisfies this product of matrixs:
![[\pi] \cdot [P]=[\pi]](https://tex.z-dn.net/?f=%5B%5Cpi%5D%20%5Ccdot%20%5BP%5D%3D%5B%5Cpi%5D)
being π the matrix of steady-state proportions and P the transition matrix.
If we multiply, we have:

Now we have to solve this equations

We choose one of the equations and solve:

Then, the steady state proportion for the U (uninvolved) fraction is 0.4.
<span>One 4 is in the hundreds place and the other is in the thousands place. So thats your answer</span>