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3 years ago

15

Write two equivalent fractions 3/6=?/?x?/?=?/?

2 answers:

babunello [35]3 years ago

6 0

1/2 and 6/12 is my 2 answers

please can i have a brainlier the crown in the right hand corner on the bottom

Hitman42 [59]3 years ago

5 0

Two equivalent fractions to 3/6 are...
6/12 (Numerator and denominator both multiplied by 2)
12/24 (Numerator and denominator both multiplied by 4)
Since this is exactly half, for this equation you can use almost any number. Just think of it, and multiply it by two! That will be your fraction. I hope this helps you, good luck ;)

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A sample of final exam scores is normally distributed with a mean equal to 23 and a variance equal to 16. Part (a) What percenta

deff fn [24]

Answer:

Let X = score of final exam.

X~normal(23, 16)

(a)

percentage of score between 19 and 27

= P(19 < X < 27)

= P((19-23) / sqrt(16) < Z < (27 - 23) / sqrt(16))

= P(-1 < Z < 1)

= 1 - P(Z <= -1) - P(Z >= 1)

= 1 - P(Z >= 1) - P(Z >= 1)

= 1 - 2*P(Z >= 1)

= 1 - 2(0.1587)

= 0.6826

= 68.26%

According to Normal Distribution Table

P(Z>=1) = 1 - P(Z<1) = 1-0.8413

So the final percentage is 68.26%

7 0

4 years ago

What is the answer to 5m-2=-12

Alina [70]

Answer:

m = -2

Step-by-step explanation:

5m - 2 = -12

Isolate m.

5m = -12 + 2

5m = -10

m = -10/5

m = -2

5 0

3 years ago

A) x2 - 2 = 0 resolver por factorizacion

Margarita [4]

Answer:

x = ± √2 = ± 1.4142

Step-by-step explanation:

6 0

3 years ago

What are the solutions of x^2-2x+5=0

sweet [91]

The solution of $x^{2}-2 x+5=0$ are 1 + 2i and 1 – 2i

<u>Solution:</u>

Given, equation is $x^{2}-2 x+5=0$

We have to find the roots of the given quadratic equation

Now, let us use the quadratic formula

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ --- (1)

<em><u>Let us determine the nature of roots:</u></em>

Here in $x^{2}-2 x+5=0$ a = 1 ; b = -2 ; c = 5

$b^2 - 4ac = 2^2 - 4(1)(5) = 4 - 20 = -16$

Since $b^2 - 4ac < 0$ , the roots obtained will be complex conjugates.

Now plug in values in eqn 1, we get,

$x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4 \times 1 \times 5}}{2 \times 1}$

On solving we get,

$x=\frac{2 \pm \sqrt{4-20}}{2}$

$x=\frac{2 \pm \sqrt{-16}}{2}$

$x=\frac{2 \pm \sqrt{16} \times \sqrt{-1}}{2}$

we know that square root of -1 is "i" which is a complex number

$\begin{array}{l}{\mathrm{x}=\frac{2 \pm 4 i}{2}} \\\\ {\mathrm{x}=1 \pm 2 i}\end{array}$

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i

6 0

3 years ago

A recipe calls for 2 teaspoons of vanilla and 3/4 cup of sugar. Compute the unit rate for vanilla to sugar. Show your work.

BabaBlast [244]

For every 1 vanilla 4 are sugar???????? Im guessing

4 0

3 years ago