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madreJ [45]
3 years ago
9

What is the exponential regression equation that fits these data?

Mathematics
2 answers:
Elis [28]3 years ago
6 0

Answer: it is y=2.26x3.02^x

Step-by-step explanation:

Rudik [331]3 years ago
6 0

Answer:

2.26x3.02^x

Step-by-step explanation:

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If I had a 10 dollars and they all had to be coined but you only have 6 quarters how would you do that??
spayn [35]

Answer:

go to a bank. idk because u have 6 quarters( $1.50) so u need $9.50

Step-by-step explanation:


6 0
3 years ago
The figure shows a person estimating the height of a tree by looking at the
FrozenT [24]

Answer:

The proportion that can be used to estimate the height of the tree is option;

A. \dfrac{h}{12} = \dfrac{6}{5}

Step-by-step explanation:

The given parameters in the question are;

The medium through which the person looks at the top of the tree = A mirror

The angle formed by the person and the tree with the ground = Right angles = 90°

The distance of the person from the mirror, d₁ = 5 ft.

The height of the person, h₁ = 6 ft.

The distance of the tree from the mirror, d₂ = 12 ft.

The angle formed by the incident light from the tree on the mirror, θ₁ = The angle of the reflected light from the mirror to the person, θ₂

Let 'A', 'B', 'M', 'T', and 'R' represent the location of the point at the top of the person's head, the location of the point at the person's feet, the location of the mirror, the location of the top of the tree and the location of the root collar of the tree, we have;

TR in ΔMRT = The height of the tree = h, and right triangles ΔABM and ΔMRT are similar

The corresponding legs are;

The height of the person and the height of the tree, which are AB = 6 ft. and TR = h, respectively

The distances of the person and the tree from the mirror, which are BM = 5 ft. and MR = 12 ft. respectively

∴ The angle formed by the incident light from the tree on the mirror, θ₁ = ∠TMR

The angle of the reflected light from the mirror to the person, θ₂ = ∠AMB

Given that θ₁ = θ₂, we have;

tan(θ₁) = tan(θ₂)

∴ tan(∠TMR) = tan(∠AMB)

tan\angle X = \dfrac{Opposite \ leg \ length \ to \ reference \ angle}{Adjacent \ leg \ length \ to \ reference \ angle}

tan(\angle TMR) = \dfrac{TR}{MR} = \dfrac{h}{12}

tan(\angle AMB) = \dfrac{AB}{BM} = \dfrac{6}{5}

From tan(∠TMR) = tan(∠AMB), we have;

\dfrac{h}{12} = \dfrac{6}{5}

\therefore h = \dfrac{6 \, ft.}{5 \, ft.} \times 12 \, ft. = 14.4 \, ft.

The height of the tree, h = 14.4 ft.

Therefore, from the proportion \dfrac{h}{12} = \dfrac{6}{5} the height of the tree can be estimated.

3 0
3 years ago
Maths ,Please help with mark brainliest
AfilCa [17]
In the table states the frequency of the marbles. It says in the 40 tries she had a frequency of 24 marbles that are yellow and for green it states the frequency is 16 marbles for green.
4 0
3 years ago
Please, please help me! I don't even know where to start with solving this...
zvonat [6]
Factorize the left hand side and equate the factors to zero.

Then, use the notation that : sec x = 1/cosx and csc x = 1/sinx

Result: x = ± π3 + 2πk , k∈Z

3 0
4 years ago
Aiko jumped rope for an amazing 20 minutes. She stoped at 8:05. When did she start jumping?
marissa [1.9K]
If she stopped at 8;05, and she started 20 minutes earlier, just imaging a clock at 8:05 and turn back time 20 minutes.

Five minutes would be 8:00, ten minutes is 7:55, fifteen minutes is 7:50, and twenty minutes is 7:45. This, she started at 7:45
4 0
3 years ago
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