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Mnenie [13.5K]
3 years ago
7

A social science book comprise of two sections: geography and civics in the ratio 4:3. How much of each type of content will be

needed to make a book of 490 pages?
please help i will mark u as brainest
Mathematics
1 answer:
DaniilM [7]3 years ago
6 0

Answer:

280 and 210

Step-by-step explanation:

For every 4 pages there has to be three more

Therefore we divide the number of pages total by 7

= 70

Geography = 70 * 4 = 280

Civics = 70 * 3 = 210

We add these together to check we have the correct number of pages

We know that the ratio is 4:3 as we multiplied those numbers with 70 respectively

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Two pools are leaking, after 15 minutes pool A has leaked 2/3 gallon, after 20 minutes pool B has leaked 2/3 gallon. Which pool
shepuryov [24]

Answer:

Pool A.

Step-by-step explanation:

This can be solved through ratios. You would write it as \frac{gallons}{minutes} So, \frac{2/3}{15} for the first one, and \frac{2/3}{20} for the second. You might want to use a calculator for that part, but you could also change the gallons to cups, which gives you a much better number of 10.515. So, \frac{10.515}{15} = 0.701, and \frac{10.515}{20} = 0.52575 So, pool A is at a faster rate. If you want it in gallons per minute, it's by 0.01 (with the 1 repeating) gallons per minute. By cups, it's 0.17525 cups per minute.

(The reason I did not do this by cross multiplying and dividing ratios is because it gives you the exact same answer if you are finding it per one, as I am here with per one minute. You can do it this way, it just wastes a bit of time.)

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3 years ago
g A law firm has six senior and seven junior partners. A committee of three partners is selected at random to represent the firm
expeople1 [14]

Answer:

133/143

Step-by-step explanation:

Let S be the sample space

Let E be the event of selecting three committee partners with at least one junior partner.

Partners in the law firm include:

Senior partners = 6

Junior partners = 7

Total partners = 13

n(S) = number of ways of selecting 3 partners from 13 = 13C3

n(S) = 13C3 = 13!/(10!3!) = (13x12x11)/(3x2x1) = 286

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(2 senior and 1 junior) or ( 1 senior and 2 junior) or (3 junior).

Therefore, the required number of way is given below:

= (6C2 x 7C1) + (6C1 x 7C2) + 7C3

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Therefore, the probability P(E) that at least one of the junior partners is on the​ committee is given below:

P(E) = n(E) /n(S)

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P(E) = 133/143

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