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3 years ago

FACTOR EACH EXPRESSION, IF IT CANT BE FACTORED WRITE CANNOT BE FACTORED. 1. 4x+12

Mathematics

2 answers:

8090 [49]3 years ago

8 0

Answer:

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Step-by-step explanation:

dimaraw [331]3 years ago

4 0

1.) 4(x+3)
Find the GCF, Greatest Common Factor, of 4x and 12.
4x=2*2*x
12=3*2*2
The greatest common factor is 4. Put this outside of the parentheses. (You would multiply the 2*2)
Then, put the rest of the factors as a sum. (Only the factors on the same line.)
Solution: 4(x+3)

To check, distribute to see if it works.

4x+12

2.) 2(4r+7)
Find the GCF of 8r and 14
8r=2*2*2*r
14= -1*7*2
The greatest common factor is 2. (There is only 1 two, so you would not multiply them.)
Then, put the rest of the factors as a sum. (Only the factors on the same line.)
Multiply the 2*2*r as one addend and the -1*7 as the other.
Solution: 2(4r-7)

To check, distribute to see if it works.

8r-14

Do you get it now?

3.) 5(x+7)
4.) 7(2x+1)
5.) Cannot be factored.

32x-15
Find the GCF of 32x and -15

32x: 2*2*2*2*2*x
-15: -1*5*3

Because there are no similar factors other than 1, it cannot be factored.

6.) 8(4x+3)
7.) 3(2x-3)
8.) 24(1x+2)
9.) 9(-2x+8)
10.) Cannot be factored
11.) 8(1x+3)
12.) 50(1x+5)

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Slope of a line perpendicular to 5x -9y = 1

Oksana_A [137]

I think it would be y=(-9/5)x -1/9

8 0

3 years ago

A Food Marketing Institute found that 39% of households spend more than $125 a week on groceries. Assume the population proporti

Anuta_ua [19.1K]

Answer:

0.6210

Step-by-step explanation:

Given that a Food Marketing Institute found that 39% of households spend more than $125 a week on groceries

Sample size n =87

Sample proportion will follow a normal distribution with p =0.39

and standard error = $\sqrt{\frac{0.39(1-0.39)}{87} } \\=0.0523$

the probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41

= $P(0.29$

There is 0.6210 probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41

7 0

3 years ago

Which of the following is a characteristic of the circumcenter of a triangle? A. It is the center of the circle that can be insc

ki77a [65]

Answer is A. It is the center of the circle that can be inscribed in a given triangle
Explanation
The circumcenter is called ”the circumcenter” because it is the center of the circle that ”circumscribes” the triangle.

6 0

2 years ago

How to answer because I struggle to answer

SpyIntel [72]

5: AA 47=47 36=36 similar

6: SSS 32/16 =2, 24/12 =2, 9/4.5 = 2 similar

7: SAS 72/53= 1.3, 55=55, 48/12 = 4 not similar

8: SAS 45/15= 3, 54=54, 9/3=3 Similar

9.SAS 20/10 =2, 10/8 = 1.25 not similar

10.SAS 32/14= 2.29, 46=46, 12/7= 1.79 not similar

5 0

3 years ago

In a study of the accuracy of fast food drive-through orders, Restaurant A had 229229 accurate orders and 7070 that were not ac

tiny-mole [99]

Answer:

a) 90% Confidence interval for true proportion of orders that are not accurate

= (0.194, 0.274)

In percentage terms, (19.4%, 27.4%)

b) Since the two confidence intervals overlap, neither restaurant appears to have a significantly different percentage of orders that are not accurate.

Step-by-step explanation:

a) Confidence Interval for the population proportion of orders that are not accurate is basically an interval of range of values where the true population proportion of orders that are not accurate can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample proportion) ± (Margin of error)

Sample proportion of orders that were not accurate = 70 ÷ (70 + 229) = 0.2341

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error)

Critical value at 90% confidence interval for sample size of (70+229=299) is obtained from the z-tables because although, the population standard deviation is not known, the sample size is large enough.

Critical value = 1.645 (from the z-tables)

Standard error of the mean = σₓ = √[p(1-p)/N]

p = sample proportion of orders that are not accurate = 0.2341

n = sample size = 299

σₓ = √(0.2341×0.7659/299) = 0.02449

95% Confidence Interval = (Sample proportion) ± [(Critical value) × (standard Error)]

CI = 0.2341 ± (1.645 × 0.02449)

CI = 0.2341 ± 0.04028

90% CI = (0.19382, 0.27438)

90% Confidence interval = (0.194, 0.274)

b) Confidence Interval for true proportion of orders that are not accurate

For Restaurant A = (0.194, 0.274)

For Restaurant B = (0.216, 0.297)

There is overlap. For example, p = 0.235 is possible for both intervals, which means that both restaurants could have a 23.5% inaccuracy rate. If there was no overlap of the intervals, then it would be impossible for p to be the same value for both restaurants. So again, we could conclude that the restaurants could have the same inaccurate order rate due to the overlap. There just isn't enough evidence to suggest that the true percentage of orders that are not accurate for the 2 restaurants are very different.

Hope this Helps!!!

5 0

3 years ago