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lbvjy [14]
3 years ago
12

FACTOR EACH EXPRESSION, IF IT CANT BE FACTORED WRITE CANNOT BE FACTORED. 1. 4x+12

Mathematics
2 answers:
8090 [49]3 years ago
8 0

Answer:

  0

 /l\

   l

  / \

----------------------------------------------------------------------------------------------------------------

Step-by-step explanation:

dimaraw [331]3 years ago
4 0
1.) 4(x+3)
Find the GCF, Greatest Common Factor, of 4x and 12. 
4x=2*2*x
12=3*2*2
The greatest common factor is 4. Put this outside of the parentheses.             (You would multiply the 2*2)
Then, put the rest of the factors as a sum. (Only the factors on the same line.)
Solution: 4(x+3)

To check, distribute to see if it works.

4x+12

2.) 2(4r+7)
Find the GCF of 8r and 14
8r=2*2*2*r
14= -1*7*2
The greatest common factor is 2.                                                                 (There is only 1 two, so you would not multiply them.)
Then, put the rest of the factors as a sum. (Only the factors on the same line.)
Multiply the 2*2*r as one addend and the -1*7 as the other.
Solution: 2(4r-7)

To check, distribute to see if it works.

8r-14

Do you get it now?

3.) 5(x+7)
4.) 7(2x+1)
5.) Cannot be factored.

32x-15
Find the GCF of 32x and -15

32x: 2*2*2*2*2*x
-15: -1*5*3

Because there are no similar factors other than 1, it cannot be factored.

6.)  8(4x+3)
7.) 3(2x-3)
8.) 24(1x+2)
9.) 9(-2x+8)
10.) Cannot be factored
11.) 8(1x+3)
12.) 50(1x+5)



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If the life in years of a television set is normally distributed with a mean of 36 years and a standard deviation of 8 years wha
TiliK225 [7]

Answer:

The company should guarantee a lifetime of less than equal to 20.95 years so that less than 3% of the television sets fail while under warranty.    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 36 years

Standard Deviation, σ = 8 years

We are given that the distribution of life of television sets is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.03.

P( X < x) = P( z < \displaystyle\frac{x - 36}{8})=0.03  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 36}{8} =-1.881\\\\x = 20.952\approx 20.95  

Thus, the company should guarantee a lifetime of less than or equal to 20.95 years so that less than 3% of the television sets fail while under warranty.

3 0
3 years ago
The measure of central angle XYZ is StartFraction 3 pi Over 4 EndFraction radians. What is the area of the shaded sector? 32Pi u
Tems11 [23]

Answer:

<em>96π units²</em>

Step-by-step explanation:

Find the diagram attached

Area of a sector is expressed as;

Area of a sector = θ/2π * πr²

Given

θ = 3π/4

r = 16

Substitute into the formula

area of the sector = (3π/4)/2π * π(16)²

area of the sector = 3π/8π * 256π

area of the sector = 3/8 * 256π

area of the sector = 3 * 32π

<em>area of the sector =96π units²</em>

5 0
3 years ago
Read 2 more answers
A school paid $31.25 for each calculator.
Sonja [21]

Answer:

500/31.25=16

Step-by-step explanation:

The school bought 16 calculators

4 0
2 years ago
WILL MARK BRINLIEST. Can someone help me wit den two questions?
VLD [36.1K]

Answer:1. B 2. D

Step-by-step explanation:

4 0
3 years ago
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Use a matrix to solve the system:
Romashka-Z-Leto [24]

Answer:

(2.83 , 1 , 4)

Step-by-step explanation:

2x+2y-z=4\\4x-2y-2z=2\\3x+3y-4z=-4\\

Rewrite these equations in matrix form

\left[\begin{array}{ccc}2&2&-1\\4&-2&-2\\3&3&-4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\

we can write it like this,

AX=B\\X=A^{-1}B

so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.

We get the inverse of matrix A,

A^{-1}=\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]  \\

now multiply the matrix with B

X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2.83\\1\\4\end{array}\right] \\

4 0
3 years ago
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