Ask question

Ask question

All categories

3 years ago

12

3/4 + 1/3 *4 1/3 / 3 1/3

2 answers:

Elena-2011 [213]3 years ago

5 0

$\frac{3}{4}+\frac{1}{3}*4\ \frac{1}{3}/3\ \frac{1}{3}\\\\\frac{3}{4}+\frac{1}{3}*(\frac{4*3}{3}+\frac{1}{3})/ (\frac{3*3}{3}+\frac{1}{3})\\\\\frac{3}{4}+\frac{4}{12}*\frac{13}{3}/\frac{10}{3}\\\frac{3}{4}+\frac{4*13}{12*3}* \frac{3}{10}\\\\\frac{3}{4}+\frac{4*13*3}{12*3*10}\\\\\frac{3}{4}+\frac{2*2*3*13}{2*2*3*3*2*5}\\\\\frac{3}{4}+\frac{13}{3*2*5}\\\\\frac{3}{4}+\frac{13}{30}\\\\\frac{3}{4}*\frac{15}{15}+\frac{13}{30}*\frac{2}{2}\\\\\frac{45}{60}+\frac{26}{60}\\\\\\\frac{71}{60}=1\ \frac{11}{60}=1.833$

Alexeev081 [22]3 years ago

4 0

<span>3/4 + 1/3 *4 1/3 / 3 1/3
=</span><span>3/4 + 1/3 * 13/3 / 10/3
= 3/4 + 13/9 * 3/10
= 3/4 + 13/30
= 45/60 + 26/60
= 71/60
= 1 11/60 (1 and 11/60)</span>

You might be interested in

In a standard deck of cards, the jack, queen, and king are "face cards." you draw a card from a standard deck. your friend peeks

vlada-n [284]

If the Ace is a face card, then the answer will be 16/52 or 4/13 simplified.
If the Ace is NOT a face card, then the answer will be 12/52 or 3/13 simplified.

6 0

3 years ago

Read 2 more answers

Theresa has $708 in her account and wishes to throw a party. She plans to include the following:

Anettt [7]

Answer:

Get rid of catering with everything u are in debt by 145.56 so get rid of catering and u r good

Step-by-step explanation:

5 0

3 years ago

An oil company fills 1/12 of a tank in 1/3 hour. At this rate, which expression can be used to determine how long it will take f

White raven [17]

Answer:

It's C

Step-by-step explanation:

Correct me if i'm wrong.

But it seems to make sense with my calculations....

6 0

3 years ago

While shopping for clothes, Daniel spent $42 less than 3 times what Curtis spent. Daniel spent $21. Write and solve an equati

ratelena [41]

Answer:

$21

Step-by-step explanation:

21+42=63

x=63:3

x=$21

5 0

3 years ago

There is a bag filled with 3 blue and 4 red marbles.

tresset_1 [31]

Using the hypergeometric distribution, it is found that there is a 0.4286 = 42.86% probability of getting 2 of the same colour.

The marbles are chosen without replacement, hence the <em>hypergeometric </em>distribution is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

In this problem:

There is a total of 3 + 4 = 7 marbles, hence N = 7.

Of those, 3 are blue, hence k = 3.

2 marbles will be taken, hence n = 2.

The probability of getting 2 of the same colour is the sum of P(X = 0), which is both red, with P(X = 2), which is both blue, then:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,7,2,3) = \frac{C_{3,0}C_{4,2}}{C_{7,2}} = 0.2857$

$P(X = 2) = h(2,7,2,3) = \frac{C_{3,2}C_{4,0}}{C_{7,2}} = 0.1429$

Hence:

$p = P(X = 0) + P(X = 2) = 0.2857 + 0.1429 = 0.4286$

0.4286 = 42.86% probability of getting 2 of the same colour.

You can learn more about the hypergeometric distribution at brainly.com/question/4818951

3 0

2 years ago