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alex41 [277]
3 years ago
14

Are those angles that are in the same position on the two lines in relation to the transversal

Mathematics
1 answer:
a_sh-v [17]3 years ago
5 0
Question is not clear
it appears you are referring to corresponding angles
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What is the value of the expression<br> Зр divided by8 + 4 when p is 32?
Otrada [13]

Answer:

-4

Step-by-step explanation:

Divide each side by '-1'.

p = -4

Simplifying

p = -4

4 0
3 years ago
The drama club is selling tickets to their play to raise money for the show's expenses. Each student ticket sells for $5 and eac
Westkost [7]

80 student tickets and 30 adult tickets must be sold to reach a $700 raise.

Since the drama club is selling tickets to their play to raise money for the show's expenses, and each student ticket sells for $ 5 and each adult ticket sells for $ 10, and the auditorium can hold a maximum of 110 people and the drama club must make a minimum of $ 700 from ticket sales to cover the show's costs, to determine one possible solution the following calculation must be performed:

  • 110 x 5 + 0 x 10 = 550
  • (700 - 550) / (10 - 5) = 150/5 = 30
  • 80 x 5 + 30 x 10 = 400 + 300 = 700

Therefore, 80 student tickets and 30 adult tickets must be sold to reach a $700 raise.

Learn more about maths in brainly.com/question/25901815

7 0
2 years ago
TRIGONOMETRY , can you solve this plz:(<br>even if you know one of them,plz help:)​
daser333 [38]

Answer:

See below

Step-by-step explanation:

\frac{1}{1-cos A} - \frac{1}{1+cos A} =2 cosec A cot A \\  \\ L. H. S.= \frac{1}{1-cos A} - \frac{1}{1+cos A} \\  \\ = \frac{1+cos A - (1 - cos A)}{(1-cos A)(1+cos A)}\\  \\ = \frac{1+cos A - 1  +  cos A}{1-cos^{2}  A}\\  \\ = \frac{2cos A }{sin^{2}  A}\\  \\ =2 .\frac{1}{sin A}.\frac{cos A }{sin  A}.\\  \\  = 2.cosec \: A.cot \: A \\  \\  = R.H.S

5 0
3 years ago
Find the equation of the line with the giving point and slope:<br><br> (4,-3), m= -1
kondaur [170]
Y+3=-x+4
y=-x+4-3
y=-x+1
8 0
3 years ago
A runner increased her distance from 9 miles to 12.5 miles a week. Find the percent increase in mileage.
kondor19780726 [428]

Answer:

<u>39 percent</u> is increase in mileage.

Thus, the correct option is B. 39%.

Step-by-step explanation:

Given:

A runner increased her distance from 9 miles to 12.5 miles a week.

Now, to find percent increase in mileage.

Previous mileage = 9 miles.

Present mileage = 12.5 miles.

<em>Mileage increase = 12.5 - 9 = 3.5 miles.</em>

Now, to get the percent increase in mileage:

\frac{Mileage\ increased}{previous\ mileage} \times 100

=\frac{3.5}{9} \times 100

=\frac{350}{9}

=38.88\%.

<u><em>Approximately the percent increase = 39%.</em></u>

Therefore, 39% is increase in mileage.

Thus, the correct option is B. 39%.

4 0
3 years ago
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