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3 years ago

I’m supposed to simplify; however, I’m absolutely clueless on how to simplify a radical. Can anyone help?

Mathematics

2 answers:

anyanavicka [17]3 years ago

7 0

Your answer simplified should be
$-6 \sqrt{30}$

erik [133]3 years ago

6 0

Simplify the following:
-2×3 sqrt(5) sqrt(6)
3 (-2) = -6:
-6 sqrt(5) sqrt(6)
sqrt(5) sqrt(6) = sqrt(5×6):
-6 sqrt(5×6)
5×6 = 30:
Answer: -6 sqrt(30)

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Travka [436]

Answer:

Step-by-step explanation:

I did it on a test too

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2 years ago

Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)

GarryVolchara [31]

Question 6

1) $\overline{AB} \cong \overline{BD}$ , $\overline{CD} \perp \overline{BD}$ , O is the midpoint of $\overline{BD}$ , $\overline{AB} \cong \overline{CD}$ (given)

2) $\angle ABO, \angle ODC$ are right angles (perpendicular lines form right angles)

3) $\triangle ABO, \triangle CDO$ are right triangles (a triangle with a right angle is a right triangle)

4) $\overline{BO} \cong \overline{OD}$ (a midpoint splits a segment into two congruent parts)

5) $\triangle ABO \cong \triangle CDO$ (LL)

Question 7

1) $\angle ADC, \angle BDC$ are right angles), $\overline{AD} \cong \overline{BD}$

2) $\overline{CD} \cong \overline{CD}$ (reflexive property)

3) $\triangle CDA, \triangle CDB$ are right triangles (a triangle with a right angle is a right triangle)

4) $\triangle ADC \cong \triangle BDC$ (LL)

5) $\overline{AC} \cong \overline{BC}$ (CPCTC)

Question 8

1) $\overline{CD} \perp \overline{AB}$ , point D bisects $\overline{AB}$ (given)

2) $\angle CDA, \angle CDB$ are right angles (perpendicular lines form right angles)

3) $\triangle CDA, \triangle CDB$ are right triangles (a triangle with a right angle is a right triangle)

4) $\overline{AD} \cong \overline{DB}$ (definition of a bisector)

5) $\overline{CD} \cong \overline{CD}$ (reflexive property)

6) $\triangle ADC \cong \triangle BDC$ (LL)

7) $\angle ACD \cong \angle BCD$ (CPCTC)

8 0

1 year ago

Reduce to the simplest form. -9/6 + (-3/5)

creativ13 [48]

Answer:

$-\frac{21}{10}$ or $-2.1$ (they're the same)

Step-by-step explanation:

Simplify: $-\frac{9}{6} + (-\frac{3}{5}) = -\frac{9}{6} - \frac{3}{5}$
Find a common denominator. The LCM of 6 and 5 is 30, so multiply the numerator and the denominator by the same thing: 6 × 5 = 30, -9 × 5 = -45, 5 × 6 = 30, 3 × 6 = 18
Write the new fractions: $-\frac{45}{30} - \frac{18}{30}$
Subtract: -45/30 - 18/30 = $-\frac{63}{30} = -\frac{21}{10}$