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bearhunter [10]
4 years ago
6

I’m supposed to simplify; however, I’m absolutely clueless on how to simplify a radical. Can anyone help?

Mathematics
2 answers:
anyanavicka [17]4 years ago
7 0
Your answer simplified should be
-6 \sqrt{30}
erik [133]4 years ago
6 0
 Simplify the following:
-2×3 sqrt(5) sqrt(6)
3 (-2) = -6:
-6 sqrt(5) sqrt(6)
sqrt(5) sqrt(6) = sqrt(5×6):
-6 sqrt(5×6)
5×6 = 30:
Answer: -6 sqrt(30) 
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Solve for X. X/8 = 3 3/4 <br> A. 30 <br> B. 24 3/4 <br> C.120 <br> D.15/32
Feliz [49]
X / 8 = 3.75
X = 3.75 * 8
X = 30
6 0
3 years ago
The ball followed a path modelled by the equation h = −0.001! + 0.5 + 2.5 where h is the height of the ball in feet and is the h
Mama L [17]

The heights the balls hit a fence at 350 ft distance are 65 feet, 38 feet and 30 feet, respectively

<h3>Represent the distance-height relationship for each player’s ball as an equation, in a table and on a graph. </h3>

<u>Juan</u>

Juan's equation is given as:

h = -0.001d^2 + 0.5d + 2.5

h =

Set d to multiples of 50 from 0 to 400.

So, the table of values of Juan's function is:

d (ft)                   h(ft)

0                          2.5

50                        25

100                      42.5

150                        55

200                      62.5

250                        65

300                      62.5

350                        65

400                      42.5

See attachment for the graph of Juan's function

<u>Mark</u>

A quadratic function is represented as:

h = ad^2 + bd + c

Using the values on the table of values, we have:

c = 3 -- the constant value

So, the equation becomes

h = ad^2 + bd + 3

Using the two other values on the table of values, we have:

23 = a(50)^2 + b(50) + 3

38 = a(100)^2 + b(100) + 3

Using a graphing tool, we have:

a = -0.001

b = 0.45

So, Mark's equation is h(d) = -0.001d^2 + 0.45d + 3

See attachment for Mark's graph.

<u>Barry</u>

From the graph, we have the table of values of Barry's function to be:

d (ft)                   h(ft)

0                          2.5

50                        21

100                      35

150                       44

200                      48

250                       46

300                      41

350                       30

400                      14

450                      0

Using a graphing tool, we have the quadratic function to be:

y = -0.001x^2 +0.4x +2.5

<h3><u>The shortest and the greatest distance before hitting the ground</u></h3>

From the graphs, equations and tables, the distance travelled by the balls are:

Juan = 505 feet

Mark = 457 feet

Barry = 450 feet

This means that Juan's ball would travel the greatest distance while Barry's ball would travel the shortest.

<h3>The height the balls hit a fence at 350 ft distance</h3>

To do this, we set d = 350

From the graphs, equations and tables, the height at 350 ft by the balls are:

Juan = 65 feet

Mark = 38 feet

Barry = 30 feet

The above represents the height the balls hit the fence

Read more about quadratic functions at:

brainly.com/question/12446886

#SPJ1

4 0
2 years ago
The answer to the following q.
Katen [24]

Answer:

See below ~

Step-by-step explanation:

Given :

⇒ m∠1 = m∠2

⇒ HD = GF

=============================================================

To Prove :

<u>Δ EHD ≅ Δ EGF</u>

<u />

============================================================

Solving :

⇒ m∠1 = m∠2 (Given)

⇒ HD = GF (Given)

⇒ ∠E = ∠E (Common angle)

⇒ ΔEHD ≅ ΔEGF (AAS congruence)

3 0
1 year ago
Read 2 more answers
Given the first type of plot indicated in each pair, which of the second plots could not always be generated from it?
Kisachek [45]

Answer:

d. box plot, stem and leaf

Step-by-step explanation:

The box plot depicts the five number summary minimum, 1st quartile, median, third quartile and maximum while stem and leaf plot shows every observation in data. So, when the box plot is given, we can't generate stem and leaf plot for the data because we don't have sufficient information in this scenario i.e., we don't have every data value to generate stem and leaf plot. Whereas, If the stem and leaf plot is given first then we can generate box plot from it because we have every data value to compute 5-number summary to generate box plot.

a. From dot plot, the histogram can be generated because dot plot represents every data value in the form of dots and from every data value, we can generate histogram.

b. From dot plot, the stem and leaf plot can be generated because dot plot represents every data value in the form of dots and from every data value, we can generate stem and leaf plot.

c. From stem and leaf plot, the dot plot can be generated because stem plot represents every data value in the form of stem and leaf i.e. 12 can be represented as 1 for a stem and 2 for a leaf (1  2)  and so, from every data value we can generate dot plot.

d. From box plot, the stem and leaf plot can't be generated and the reason is explained in first paragraph. So, when the first type of plot is box plot then from it second plot stem and leaf plot can't be generated.

6 0
3 years ago
If sin 0 = 4<br> what is cos O?<br> cos 0 =<br> =<br> Simplify your answer if possible.
Tems11 [23]

Answer:

  cos(θ) = (√33)/7

Step-by-step explanation:

The relevant relation is ...

  cos(θ) = √(1 -sin²(θ))

  cos(θ) = √(1 -(4/7)²) = √(1 -16/49) = √(33/49)

  cos(θ) = (√33)/7

7 0
2 years ago
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