Okay here it is. <span>Part A: </span>
6m + 12 + 42m
48m + 12
<span>Part B: </span>
6m + 12 + 42m . used distributive property
Part C: Show that your other expression from Part A is equivalent to the given expression by substituting a number for m. (3 points)
6*0 + 12 + 42*0 = 12
<span>48*0 + 12 = 12</span>
Do u have a picture of the assignment?
8/12 4/8 4/12 is the answer for the shaded part
-294 is the difference between the highest and lowest number
Answer:
<h3>The value C(t) of the car after 5 years is $12709.</h3>
Step-by-step explanation:
Given that Landon bought a new car for $16,000 and it depreciates 4.5% every year.
<h3>To find the value C(t) of the car after 5 years:</h3>
Initial value 
Depreciation rate is 
<h3>∴ r=0.045</h3>
Period , t=5 years

Substitute the values we get



∴ 
<h3>The value C(t) of the car after 5 years is $
12709</h3>