Answer:
The correct answer would be - wildtype.
Explanation:
Let assume there are four genes which are :
A-B-C-D
In mutant first, the genotype would be:---a-b-C-D
In the mutant second, the genotype would be:--A-B-c-d
If both of these genotypes are crossed with each other, the recessive genes a, b of mutant first is dominated and masked the expression by the dominant genes present in the mutant second.
Similarly, the recessive genes of the mutant second are dominated and masked expression by the dominant genes of mutant first. This is possible only due to different genes are present in mutants.
Thus, the correct answer is - The correct answer would be - wildtype.
Answer:
Explanation:
A woman with type A blood (whose father was type O) meaning her genotype is AO mates with
Man that has type O blood (OO genotype)
Both are heterozygous for MN blood group and both also heterozygous for the FUT1 gene controlling the synthesis of the H substance (Hh)- which determines the expression of the A and B antigen.
Cross
A O M N H h
O AO OO M MM MN H HH Hh
O AO OO N MN NN h Hh hh
Type A- 1/2 O-1/2 type M- 1/4 MN-1/2 N- 1/4, type H- 3/4 h-1/4
Type A with M antigen:
1/2*1/4*3/4 = 3/32
Type A with M and N antigens:
1/2*1/2*3/4 = 3/16
Type A with N antigen:
1/2*1/4*3/4 = 3/32
Type O with M antigen:
1/2*1/4*3/4= 3/32
Type O with M and N antigens:
1/2*1/2*3/4 = 3/16
Type O with N antigen:
1/2*1/4*3/4 = 3/32.
The 3/4 value comes from the expression of Hh-3/4 (this determines if the A and B Angie will be expressed).
Yes, I believe that's why it's called the parent cell.
It inhabitants the deep waters off the coasts of mainland Australia,Tasmania as well as the waters of New Zealand.
The answer is C because he has all the following characteristics
