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Trava [24]
3 years ago
6

Emmanuel wants to tile his rectangular floor. he has two kinds of tiles to choose from, one of which is larger than the other. e

mmanuel hired your services to help him decide which tile to use.
a.what area will be covered by 7"x7" tile? 21"x21" tilwe
b.if the rectangular floor has dimension of 420" by 630"
c.how many big square tiles are needed to cove rthe rectangular floor?
d.if each small tile costs P15.00 and each big tile costs P60.00which which tile should emmanuel use to econimize in tiling his floor? why?
Mathematics
1 answer:
rjkz [21]3 years ago
8 0
A).
The 8" by 7" tile covers 49 square inches.
The 21" by 21" tile covers 441 square inches.

b).
The area of the floor is (420" x 630") = 264,600 square inches.

c).
It would take (264,600) / (441) = 600 large tiles to cover the floor.

d).
Emmanuel should use the big tiles to cover his floor.
-- A big tile costs 4 times as much as a small tile, but it has 9 times
as much area as a little tile has, so it is a better buy.
-- Plus, he would have to pay the floorman a lot more to glue down 5,400 tiles
than he will have to pay to glue down only 600 tiles.
-- Since he has hired my services to advise him, I will charge him only 15%
of the difference if he takes my advice, so he will still be money ahead.
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A cuboid in which the sum of its dimensions is 9 cm., then the sum of its edge lengths - cm. (18 or 27 or 36 or 45)​
ser-zykov [4K]

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Reasons:

The given parameters are;

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Required:

The value sum of the dimension of the edges the cuboid.

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brainly.com/question/12978944

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