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Law Incorporation [45]
3 years ago
10

Which of the following consists of electronic components that store instructions?

Computers and Technology
1 answer:
Gennadij [26K]3 years ago
8 0

Answer:

<u>(RAM) Memory</u> is the electronic component that is used to store instruction, data needed to that instructions and results of execution of these instruction.

Explanation:

Memory is the electronic component. It is made up of flip  flops. Each flip flop stores one bit of data. Flip flop is designed with the help of transistors. No. of flip flops combined together to make a larger size memory.

There are different types of memories in computer systems to accomplish different tasks. Such as RAM, ROM, Hard disk and Cache. The memory that hold instruction, their data and results after execution of that instructions is called RAM.

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What dose it need For a device to be considered a kind of computer
const2013 [10]

Answer:

Micro controller or MCU (Microcontroller Unit)

Explanation:

Micro Controller Unit is basically a computer on a chip with all components fabricated onto it. It is the core component of a computer.

A Micro Controller has:

  • Central Processing Unit CPU
  • Random access memory RAM
  • Read-only memory ROM
  • I/O peripherals
  • Timers
  • Serial COM ports

all fabricated on a single chip so that it may be connected via buses for providing the desired functionality.

<h3>I hope it will help you!</h3>
8 0
3 years ago
Read 2 more answers
Feedback is one of the basic elements games have in common<br><br> True<br> False
mixas84 [53]
True because odds of finds any game with no feedback is unheard of
7 0
3 years ago
Read 2 more answers
Write a program that takes a point (x,y) from theuser and find where does the point lies. The pointcan
agasfer [191]

Answer:

C++ Program .

#include<bits/stdc++.h>

using namespace std;

int main()

{

int x,y;//declaring two variables x and y.

string s;//declaring string s..

cout<<"enter x and y"<<endl;

cin>>x>>y;//taking input of x and y..

if(x>=0 &&y>=0) //condition for 1st quadrant..

cout<<"the point lies in 1st Quadrant"<<endl;

else if(x<=0 &&y>=0)//condition for 2nd quadrant..

cout<<"the point lies in 2nd Quadrant"<<endl;

else if(x>=0 &&y<=0)//condition for 3rd quadrant..

cout<<"the point lies in 3rd Quadrant"<<endl;

else //else it is in  4th quadrant..

cout<<"the point lies in 4th Quadrant"<<endl;

cout<<"enter n to terminate the program"<<endl;

while(cin>>s)//if the user has not entered n the program will not terminate..

{

   if(s=="n")

   {

       cout<<"the program is terminated"<<endl;

       exit(0);

   }

   cout<<"you have not entered n please enter n to terminate the program<<endl;

}

}

Explanation:

The above written program is for telling the point lies in which quadrant.I am first declaring two variables x and y.Then after that taking input of x and y after that checking in which quadrant the point lies.

Taking input of the string s declared earlier for program termination the program will keep running until the user enters n.

4 0
3 years ago
A computing company is running a set of processes every day. Each process has its own start time and finish time, during which i
Helga [31]

Answer:

Above all else, let us show that this issue has the greedy choice property.

This implies that worldwide ideal arrangement can be gotten by choosing local ideal arrangements. Presently notice the following:

The global optimal solution of the issue requests us to track down the minimum number of times process_check module should be run.

It is likewise referenced that during each running interaction, process_check module should be called atleast once. Along these lines, the minimum possible number of process_check calls happens when process_check is made close to the quantity of the processes that are run.

Along these lines, we see that the global optimal solution is shaped by choosing optimal answer for the nearby advances.

Along these lines, the issue shows greedy choice property. Thus, we can utilize a greedy algorithm for this issue.

The greedy step in this calculation is to postpone the process_check as far as might be feasible. Thus, it should be run towards the finish of each interaction. So the following algorithm can be utilized:

Sort the cycles by utilizing the completion times.

Towards the finish of the 1st process in the arranged list, run the process_check module. Right now any process that is now running is removed the arranged rundown. The main interaction is additionally removed from the sorted list.

Now repeat stage 2, till all processes are finished.

In the above mentioned algorithm, the costliest advance is the step of sorting. By utilizing the optimal sorting algorithm, for example, merge sort, we can achieve it in O(n log n) asymptotic time.

Along these lines, this greedy algorithm additionally takes O(n log n) asymptotic time complexity.

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2 years ago
what's the best mouse for fast clicking ? I play a lot of fps and a lot of pvp games I need a mouse that I can click fast with a
kondaur [170]
Alenware hp dell logtech, and i know others
7 0
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