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evablogger [386]
3 years ago
5

Routers: operate at the application layer operate only at the physical layer cannot connect two or more networks that use the sa

me type of cable may also be called TCP/IP gateways operate only at the data link layer.
Computers and Technology
1 answer:
Ket [755]3 years ago
5 0

Answer:

The correct option to the following question is option (D) may also be called TCP/IP gateways.

Explanation:

Commonly, Internet Protocol routers are referred to as the internet gateways because between the networks the routers use an IP address for routing the packets.

In the TCP/IP structure, the router works at several layers and also the router can select their path for the flow of the data because they know where is the other routers.

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What will be the value of “sumtotal” when this code is executed?
Lelu [443]

Answer:

2

Explanation:

if-else is the statement that is used for checking the condition and if the condition is True, then execute the statement otherwise not executed.

initially, the value of n1 = 3, n2 = 6, n3 = 2, sumtotal = 4.

after that, if statement checks for the condition.

3 != 4

condition is TRUE, then the statement sumtotal -= n3; will be executed.

write the statement in simple form:

sumtotal = sumtotal - n3;

so, sumtotal = 4-2 = 2.

after that, the program does not check the further and exit the if-else statement.

Therefore, the answer is 2.

4 0
3 years ago
Weak Induction
slega [8]

Answer:

Following are the answer to this question:

Explanation:

In option 1:

The value of n is= 7, which is (base case)

\to 3^7

when n=k for the true condition:

\to 3^k

when n=k+1 it tests the value:

\to 3^{(k+1)}= 3^k,3\\\to < (k!) 3 \ substituting \ equation \\\to

since k>6  hence the value is KH>3 hence proved.

In option 2:

when:

for n=1:(base case)

\log(1!)

0<=0 \\ condition is true

when the above statement holds value n=1

when n=k

\log(k!)

when n=k+1

\log(k+1)!=\log(k!)+\log(k+1)\\

             

\because k \log k      [\therefore KH>K \Rightarrow  \log(KH>\loK)]

In option 3:

when n=1:

A_1 \cup B=A_1 \cup B\\\\

when n=k

\to (A_1\cap A_2 \cap.....A_k) \cup B\\=(A_1\cup B) \cap(A_2\cup B_2)....(A_k \capB).....(a)\\\to n= k+1\\ \to (A_1\cap A_2 \cap.....A_{kH}) \cup B= (A_1\cup B)\\\\\to  [(A_1\cap A_2 \cap.....A_{k}) \cup B]\cap (A_{KH}\cup B)\\\\\to  [(A_1\cup B) \cap (A_2 \cup B) \cap (A_3\cup B).....(A_k\cup B)\cap (A_{k+1} \cup B)\\\\  \ \ \ \ \ \ substituting \ equation \ a \\\\

hence n=k+1 is true.

7 0
3 years ago
Who owns the internet? <br><br> A.) Nobody<br> B.) W3C<br> C.) NSCA<br> D.) The US Military
crimeas [40]

your answe is A i believe


I hope that this helps

and that you have a wonderful day

3 0
2 years ago
When individuals are purchasing a computer, they sometimes might get the most expensive computer they can afford. Why might this
timama [110]

Answer:

Expensive is not always better

Explanation:

So I build 2 computers ok

Computer 1: Price 1,999$

<u>Whats Included:</u>

  • Antivirus
  • Anti-Over-Heat
  • Windows 8 Operating Software
  • Free VPN (For Life)
  • 24/7 Support
  • 1 year warranty
  • 3/5 Star Reviews | Main Review Type: Parts Breaking Inside

Computer 2: Price 799$

<u>Whats Included:</u>

  • Anti Virus
  • Anti Over-Heat
  • 1 Year Warranty
  • Windows 10 Operating Software
  • 24/7 Support
  • 10 Year Warranty
  • 4/5 Star Reviews | Main Review Type: Runs Smooth
  • No VPN

<h2>So Computer 2 Has better reviews and a 10 year warranty over computer 1's 1 year warranty</h2>
8 0
2 years ago
SummaryIn this lab, you complete a partially written C++ program that includes a function named multiplyNumbers() that multiplie
Maru [420]

Answer:

Declare the method prototype using:

void multiplyNumbers(int x, int y,int &product);

Call the function using:

multiplyNumbers(num1, num2,product);

Lastly, the method is as follows:

void multiplyNumbers (int x, int y,int &product) {

  product = x * y;

  return; }

Explanation:

Declare the method prototype using

void multiplyNumbers(int x, int y,int &product);

Call the function using

multiplyNumbers(num1, num2,product);

The method is as follows; the & written in front of product implies that product is passed by reference

void multiplyNumbers (int x, int y,int &product) {

This calculate the product

  product = x * y;

This returns nothing

  return; }

<em>See attachment for complete program</em>

Download cpp
5 0
3 years ago
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