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frez [133]
3 years ago
7

Does anyone know any of these two??

Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0
First Problem:

angle R and angle S are complementary which means they add to 90 degrees. Think "C" for "Complementary" and "Corner" as in a sharp 90 degree corner. That's how I remember it.

Let's solve for x
(angle R) + (angle S) = 90
(12x-3) + (7x-2) = 90
12x-3 + 7x-2 = 90
(12x+7x)+(-3-2) = 90
19x-5 = 90
19x-5+5 = 90+5
19x = 95
19x/19 = 95/19
x = 5

Since x = 5, we can say
angle R = 12x - 3
angle R = 12*5 - 3
angle R = 60 - 3
angle R = 57 degrees

Final Answer: 57 degrees

-----------------------------------------------------------

Second Problem:

Angle 1 and angle 2 "form a linear pair". This means they are adjacent and supplementary (add to 180 degrees). Put another way, they combine to form a single straight angle or line.

Let's make 
x = measure of angle 1
y = measure of angle 2

We're also told that "the measure of angle 2 is six more than twice the measure of angle 1", which basically translates to
y = 2*x + 6

Because the angles (x and y) are supplementary, we can also say
x+y = 180

So we have this system of equations
y = 2x+6
x+y = 180

Start with equation (2). Plug in the equation (1) and solve for x
x+y = 180
x+2x+6 = 180 ... note how y has been replaced with 2x+6
3x+6 = 180
3x+6-6 = 180-6
3x = 174
3x/3 = 174/3
x = 58

Now that we know x, we can find y
y = 2x+6
y = 2*58+6
y = 116+6
y = 122

Final Answer: 122 degrees
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u 1. Consider the sequence: 192, 144, 108,81 ... a. Is this sequence arithmetic or geometric? Explain, geomethe becose hoy sonet
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On Monday, it snowed 40 inches in 10 hours. On Thursday, it snowed 21 inches in 7 hours. On which day did it snow at a greater r
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On Monday

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40÷10=4

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3 years ago
What is the y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1? y = (StartFraction
Dominik [7]

By applying section formula we got that y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1 is \frac{5y_2+y_1}{6}

<h3>What is section formula ?</h3>

Let point P(x,y) cuts line joining point  A(x_1,y_1) and B(x_2,y_2)  in m_1:m_2 then coordinate of point P is equal to (\frac{m_1x_2+m_2x_1}{m_1+m_2}, \frac{m_1y_2+m_2y_1}{m_1+m_2})

Here given that point divides line segment from J to K into a ratio 5:1

So

m_1=5\\\\m_2=1

Now we have to fin y coordinate of point that divides the directed line segment from J to K into a ratio of 5:1

We can calculated y coordinate by applying section formula as :

\frac{5y_2+1y_1}{5+1}\\\\\frac{5y_2+y_1}{6}

By applying section formula we got that y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1 is \frac{5y_2+y_1}{6}

To learn more about   section formula visit:brainly.com/question/26433769

4 0
3 years ago
GIVING BRAINLIEST!! ANSWER FAST PLZZ
MakcuM [25]

Answer:

c $3.50

Step-by-step explanation:

Do $1.50 and add it to all the choices untill you get one the equals $5

6 0
3 years ago
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