Question

What is the y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1? y = (StartFraction m Over m n EndFraction) (y 2 minus y 1) y 1 –8 –5 0 6.

Answer 1

By applying section formula we got that y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1 is $\frac{5y_2+y_1}{6}$

What is section formula ?

Let point P(x,y) cuts line joining point  $A(x_1,y_1)$ and $B(x_2,y_2)$  in $m_1:m_2$ then coordinate of point P is equal to $(\frac{m_1x_2+m_2x_1}{m_1+m_2}, \frac{m_1y_2+m_2y_1}{m_1+m_2})$

Here given that point divides line segment from J to K into a ratio 5:1

So

$m_1=5\\\\m_2=1$

Now we have to fin y coordinate of point that divides the directed line segment from J to K into a ratio of 5:1

We can calculated y coordinate by applying section formula as :

$\frac{5y_2+1y_1}{5+1}\\\\\frac{5y_2+y_1}{6}$

By applying section formula we got that y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1 is $\frac{5y_2+y_1}{6}$

To learn more about   section formula visit:brainly.com/question/26433769