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3 years ago

Write an equation of the line that is parallel to the line y = -x + 4 and passes through the points 0, 10.

1 answer:

8 0

Line parallel to y = -x+4 will have the same gradient.
Gradient = -1
Equation of line: y = -x + c
Point : (0,10) replace in the above equation
y = -x + c
10 = -0 + c
c = 10
Equation is: y = -x + 10

Hope it helped!

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X²+y²-6x+14y-1=0 and please show your work so I can learn

Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

$x^2 + y^2 -6x+14y-1=0$

We need to use the Quadratic Formula*

$x =\frac{-b+\sqrt{b^2}-4ac }{2a}$ , $\frac{-b-\sqrt{b^2} -4ac }{2a}$

Thus, given the problem:

$a = 1, b=-6, c=y^2+14y-1$

So now we just need to plug them in the Quadratic Formula*

$x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$ , $x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$

As you can see, it is a mess right now. Therefore, we need to simplify it

$x=\frac{6+2\sqrt{10-y^2-14y} }{2}$ , $x = \frac{6-2\sqrt{10-y^2-14y} }{2}$

Now that's get us to the final solution:

$x=3+\sqrt{10-y^2-14y}$ , $x=3-\sqrt{10-y^2-14y}$

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

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3 years ago

If the scale factor is

klemol [59]

If the scale factor is 1/5, then the area of the preimage is multiplied by 0.2 or 1/5 to calculate the area of the new image.

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3 years ago

The larger of two numbers is five more than twice the smaller number. The sum of the two numbers is 38. Find the numbers.

Damm [24]

Answer:

I would set this up as:

let: lesser number = x

greater number = 2x + 5

Restating the word problem:

lesser number + greater number = 38

x + 2x + 5 = 38

Solving: 3x + 5 = 38

- 5 -5

---------------

3x = 33

--- ---

3 3

x = 11

Substitution for the greater number:

2(11) + 5

22 + 5

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Step-by-step explanation: I just did a test and got 100%

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Marta_Voda [28]

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Step-by-step explanation:

reason for is because when you add all the like terms you end up with c

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