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3 years ago

PLease help i know its simple i just suck at math 5(3^5+20^2)

Mathematics

1 answer:

gulaghasi [49]3 years ago

6 0

Hey! The answer's 3215.

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8=8^4x? What goes on the question mark?

Lerok [7]

Answer:

8^1 = 8

So, x has to be 1/4 to make the exponent 1, and to make it equal to 8.

Let me know if this helps!

4 0

3 years ago

What is the slope of the line that passes through (-2,4) and (4,1)

bagirrra123 [75]

Answer:

The slope is -1 /2 or -0.5

Step-by-step explanation:

use the formula y2-y1 / x2-x1

5 0

3 years ago

Please Help Meeeeee, Amanda's house is due west of Stamford and due south of Newport. Stamford is 12 kilometers from Amanda's ho

lubasha [3.4K]

Answer:

5 km

Step-by-step explanation:

It helps to draw a diagram.

The triangle between Stamford, Newport, and Amanda's house is a right triangle with one leg of length 12 and hypotenuse 13. The Pythagorean theorem can be used to find the remaining leg:

13² = 12² + (distance to Newport)²

169 -144 = (distance to Newport)²

√25 = 5 = distance to Newport

Newport is 5 km from Amanda's house.

_____

It can be useful to remember this right triangle. 5-12-13 right triangles show up in a number of algebra and geometry problems.

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3 years ago

What is the slope-intercept form of the function that contains the points (5, 6 and (9, 14?the slope-intercept form of the funct

alina1380 [7]

Correct!

The slope is (14-6)/(9-5) = 8/4 = 2;

<span>the slope-intercept form of the function that contains the points (5, 6) and (9, 14) is y - 6 = 2( x - 5 );
Then, y - 6 =2x - 10;
y = 2x - 4 ;</span>

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4 years ago

Solve the inequality <br><br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2x%7D%7Bx%20%2B%203%7D%20%20%5Cleqslant%203" id="Tex

Fofino [41]

$Domain:x\neq-3\\\\\dfrac{2x}{x+3}\leq3\qquad\text{subtract 3 from both sides}\\\\\dfrac{2x}{x+3}-3\leq0\\\\\dfrac{2x}{x+3}-\dfrac{3(x+3)}{x+3}\leq0\\\\\dfrac{2x}{x+3}-\dfrac{3x+9}{x+3}\leq0\\\\\dfrac{2x-(3x+9)}{x+3}\leq0\\\\\dfrac{2x-3x-9}{x+3}\leq0\\\\\dfrac{-x-9}{x+3}\leq0\Rightarrow(x+3)(-x-9)\leq0\\\\x=-3,\ x=-9\\\\x\in(-\infty,\ -9]\ \cup\ (-3,\ \infty)$

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3 years ago