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Ronch [10]
4 years ago
14

Consider the following geometric sequence: -5, 10, -20, 40,..... if the explicit formula for the sequence above is expressed in

the form an=B•C ^N-1 determine the values of B and C
Mathematics
2 answers:
Dima020 [189]4 years ago
6 0
To solve this we are going to use the formula for the nth term of a geometric sequence: a_{n}=a_{1}r^{n-1}
where 
a_{n} is the nth term 
a_{1} is the first term 
r is the common ratio 
n is the place of the term in the sequence

Notice that we can infer for our problem that B=a_{1} and C=r.

Now, to find our common ratio, we are going to use the formula r= \frac{a_{n}}{a_{n-1} }
where
a_{n} is the current term in the sequence 
a_{n-1} is the previous term in the sequence
for a_{n}=10 and a_{n-1}=-5:
r= \frac{10}{-5}
r=-2

Since r=C, we can conclude that C=-2.

Notice that the first therm of our geometric sequence is -5, so a_{1}=-5. Since B=a_{1}, we can conclude that B=-5.

We can conclude that the values of B and C in our geometric sequence are: B=-5 and C=-2.
Marizza181 [45]4 years ago
6 0
When solving the geometric sequence look for what how the sequence is set up from the number it starts with and how the sequence is developed.
b=-5
c=-2
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What is the equation of the following line written in slope-intercept form?
ladessa [460]

Answer:

y = -2/3 x - 13/3

Step-by-step explanation:

We have one point at (-5,-1)  and there is another point at (1,-5)

The slope is

m= (y2-y1)/(x2-x1)

   = (-5--1)/(1--5)

  = (-5+1)/(1+5)

  = -4/6

=-2/3

The point slope form of the equation is

y-y1 = m(x-x1)

y--1 = -2/3(x--5)

y+1 =-2/3( x+5)

Distribute

y+1 = -2/3 x -10/3

Subtract 1 from each side

y +1-1 = -2/3 x -10/3 -1

Get a common denominator

y = -2/3 x -10/3 -3/3

y = -2/3 x - 13/3

6 0
3 years ago
A swimming club has 72 trainers who teach swimming and 30 of those trainers also teach diving. There are 28 trainers who do not
dsp73

Answer:

Step-by-step explanation:

tabel

.52, .48, 1

.84,.16,1

.67,.33,1

6 0
3 years ago
PLEASE HELP I'LL GIVE BRAINLIEST!!! The first barn contained 3 times more hay than the second one. After 20 tons of hay were rem
shepuryov [24]

Answer:

First Barn contained = 90 tons

Second barn contained = 30 tons

Step-by-step explanation:

Let us suppose that second barn contains x tons of Hay

Now according to given condition

First Barn Contain = 3 *x = 3x

According to other condition

20 tons removed from first barn i.e. 3x - 20 and 20 tons were added to second barn i.e. x + 20

the amount of hay in second barn which is x + 20 is equal to 5 / 7 of the hay remaining in first barn which is 3x-20

So in mathematical form it could be written as

x + 20 = \frac{5}{7}*(3x-20)

To find hay in each barn

We have the equation

x + 20 = \frac{5}{7}*(3x-20)

Multiplying both sides of equation by 7

7(x+20)=\frac{5*7}{7}*(3x-20)

7(x+20)=5(3x-20)

7x + 140 = 15 x - 100

adding 100 on both sides gives

7x + 140 + 100 = 15x - 100 + 100

7x + 240 = 15 x

Subtracting 7x from both sides

7x + 240 - 7x = 15 x - 7x

240 = 8x

or

8x = 240

Dividing both sides by 8

8x / 8 = 240 / 8

x = 30 tons

so second barn contained = 30 tons of hay

now

First barn contained = 3 * x

as x = 30

so putting the value

First barn contained = 3 * 30

First Barn contained = 90 tons


5 0
3 years ago
The price of a house is originally listed at $225,000. The owners are having a hard time selling it and decide to reduce the pri
Darina [25.2K]
Percent decrease : (original number - new number) / original number..*100
                            = (225,000 - 191,250) / 225,000.....* 100
                            = 33,750 / 225,000....* 100
                            = 0.15 * 100
                            = 15% decrease <==
5 0
4 years ago
In a small private college, 80 students play baseball, 70 students play football, 50 students play basketball, and 550 students
motikmotik

Answer:

1/5, or 20%

#FreeMelvin

4 0
3 years ago
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