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3 years ago

9

What is the volume of a cube, if the length of one side is 12 cm?

2 answers:

irinina [24]3 years ago

5 0

The formula for the volume of a cube is length times width times height. Since the sides of a cube are all the same, it would be 12 cubed (12 x 12 x 12). The answer is 1,728 centimeters cubed.

Mice21 [21]3 years ago

5 0

The answer would be 1,728 because volume
is length times width times height, so 12x12x12.

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Vincent has the following data:

Igoryamba

Step-by-step explanation:

it is 18 because 18 is greater than 17 and my aunt is a teacher and told me the answer

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3 years ago

Solve the system of equations by graphing. Look at the picture. Will Mark Brainliest

aleksandr82 [10.1K]

Answer:

See below

Step-by-step explanation:

<h3>Graphing:</h3>

we are given two functions

$\displaystyle \begin{cases}f(x) = - x + 5 \\ g(x) = {x}^{2} - 3x + 2\end{cases}$

where f(x) is a <em>linear</em><em> </em><em>function</em> and g(x) is a <em>q</em><em>uadratic </em>function

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the Black-table is attached

let's graph g(x):

the picture is attached

hence, the graph should be

the graph is attached

<h3>solutions stating:</h3>

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3 years ago

There are 210210210 students in a twelfth grade high school class. 909090 of these students have at least one sister and 1051051

BlackZzzverrR [31]

Answer:

(1) The value of P (A) is 0.4286.

(2) The value of P (B) is 0.50.

(3) The value of P (A ∩ B) is 0.2143.

(4) The the value of P (B|A) is 0.50.

(5) The events <em>A</em> and <em>B</em> are independent.

Step-by-step explanation:

The events are defined as follows:

<em>A</em> = a student in the class has a sister

<em>B</em> = a student has a brother

The information provided is:

<em>N</em> = 210

n (A) = 90

n (B) = 105

n (A ∩ B) = 45

The probability of an event <em>E</em> is the ratio of the favorable number of outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

The conditional probability of an event <em>X</em> provided that another event <em>Y</em> has already occurred is:

$P(X|Y)=\frac{P(A\cap Y)}{P(Y)}$

If the events <em>X</em> and <em>Y</em> are independent then,

$P(X|Y)=P(X)$

(1)

Compute the probability of event <em>A</em> as follows:

$P(A)=\frac{n(A)}{N}\\\\=\frac{90}{210}\\\\=0.4286$

The value of P (A) is 0.4286.

(2)

Compute the probability of event <em>B</em> as follows:

$P(B)=\frac{n(B)}{N}\\\\=\frac{105}{210}\\\\=0.50$

The value of P (B) is 0.50.

(3)

Compute the probability of event <em>A</em> and <em>B</em> as follows:

$P(A\cap B)=\frac{n(A\cap B)}{N}\\\\=\frac{45}{210}\\\\=0.2143$

The value of P (A ∩ B) is 0.2143.

(4)

Compute the probability of <em>B</em> given <em>A</em> as follows:

$P(B|A)=\frac{P(A\cap B)}{P(A)}\\\\=\frac{0.2143}{0.4286}\\\\=0.50$

The the value of P (B|A) is 0.50.

(5)

The value of P (B|A) = 0.50 = P (B).

Thus, the events <em>A</em> and <em>B</em> are independent.

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4 years ago

2. Use the image below to answer problems A-C. Show all work.

Yakvenalex [24]

<span>A. Calculate the value of x.</span>

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3 years ago

Does anyone know how to solve this?

Ivahew [28]

Answer:

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3 years ago