We know that
speed=distance/time
solve for time
time=distance/speed
in this problem
<span>Marco runs at a rate of 6 miles per hour.
</span><span>Fernando funs at a rate of 7.2 miles per hour
Difference=7.2-6=1.2 miles/hour
so
speed=1.2 miles/hour
distance=0.3 miles
time=?
</span>time=distance/speed-----> 0.3/1.2-----> 0.25 hour-----> 0.25*60=15 minutes
<span>
the answer is
0.25 hour (15 minutes)
Alternative Method
Let
x---------> Fernando's distance when Marco is 0.3 miles apart
</span>Fernando funs at a rate of 7.2 miles per hour
<span>for distance =x
time=x/7.2------> equation 1
</span>Marco runs at a rate of 6 miles per hour.
for distance=x-0.30
time=(x-0.30)/6------> equation 2
equate equation 1 and equation 2
7.2*(x-0.3)=6x-----> 7.2x-2.16=6x
7.2x-6x=2.16------> x=2.16/1.2-------> x=1.8 miles
time=x/7.2-----1.8/7.2=0.25 hour
Answer:
The equilibrium quantity is 26.4
Step-by-step explanation:
Given
Required
Determine the equilibrium quantity
First, we need to determine the equilibrium by equating Qd to Qs
i.e.
This gives:
Collect Like Terms
Solve for P
This is the equilibrium price.
Substitute 2.4 for P in any of the quantity functions to give the equilibrium quantity:
<em>Hence, the equilibrium quantity is 26.4</em>
Number 15 is no solution.
Number 27 is that x has to be between -2 or 2.
This could be explained as -2≤x≤2
19/38 = 1/2 (divided top and bottom by 19)
so
34 X 19/38
= 34 X 1/2
= 34/2
= 17/1
Answer
17/1 (or 17)
