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Serjik [45]
2 years ago
8

If the temperature on a thermometer is 7 degrees and rises 5 degrees what is the new reading

Mathematics
1 answer:
kompoz [17]2 years ago
3 0
12 degrees

7 + 5 = 12
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What is the circumference of a circle with area 50cm2. Give your answer to three significant figures.
Mnenie [13.5K]

Answer:

c = 25.1

Step-by-step explanation:

C = 2\sqrt{pi A}

C = 2 \sqrt{3.14 * 50 }

C = 25.1

Mark me brainly plz

7 0
3 years ago
50 points! PLEASE HELP WITH THIS! Show how you got the answers!!! WIll mark as brainliest!!! DONT ANSWER IF YOU DONT KNOW IT!!
JulsSmile [24]

Answer:

x=4

x=17.9

Step-by-step explanation:

For the first diagram.

cos(45°)=x/4√2

x=4√2cos(45°)

x=4

For the second diagram

tan(38°)=14/x

0.781=14/x

x=14/0.781=17.9

7 0
2 years ago
PLEASE HURRY
Inga [223]
The points: (0,4), (1,8),(2,10) is NOT a linear function as it doesnt pass the verticle line test. Linear function should always be in a straight line. Examples of linear functions: 4x + 3y = 6. Examples of nonlinear functions: y = 8x^2 + 10.
4 0
2 years ago
Read 2 more answers
A manufacturing process produces semiconductor chips with a known failure rate of . If a random sample of chips is selected, app
AleksandrR [38]

Answer:

The probability that at least 14 of the chips will be defective is 0.6664.

Step-by-step explanation:

The complete question is:

A manufacturing process produces semiconductor chips with a known failure rate of 5.4%. If a random sample of 300 chips is selected, approximate the probability that at least 14 will be defective. Use the normal approximation to the binomial with a correction for continuity .

Solution:

Let <em>X</em> = number of defective chips.

The probability that a chip is defective is, <em>p</em> = 0.054.

A random sample of <em>n</em> = 300 chips is selected.

A chip is defective or not is independent of the other chips.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 300 and <em>p</em> = 0.054.

But the sample selected is too large.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=300\times 0.054=16.2>10\\n(1-p)=300\times (1-0.054)=283.8>10

Thus, a Normal approximation to binomial can be applied.

So,  X\sim N(\mu =16.2,\ \sigma^{2}=15.3252).

Compute the probability that at least 14 of the 300 chips will be defective as follows:

Use continuity correction:

P (X ≥ 14) = P (X > 14 + 0.50)

               = P (X > 14.50)

               =P(\frac{X-\mu}{\sigma}>\frac{14.50-16.20}{\sqrt{15.3252}})

                =P(Z>-0.43)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 14 of the chips will be defective is 0.6664.

5 0
2 years ago
State if the triangle are congruent by sss sas asa aas or not congruent
Gnesinka [82]

Answer:

(a) SSS

.........................

7 0
2 years ago
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