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Alika [10]
3 years ago
9

3/8 + 4/8 = ? please help

Mathematics
2 answers:
maksim [4K]3 years ago
4 0
The answer is going to be 7/8. hope that helped
bulgar [2K]3 years ago
3 0
Hello!

This is really easy, all you have to do is add the numerators.. (3 & 4)
With this, your answer is 7/8.

Hope this helps! ☺♥
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2y - 4x = 4 Rewrite:
USPshnik [31]

Answer:

y - 2x = 2

Step-by-step explanation:

2y - 4x = 4

2(y - 2x) = 4  | : 2

y - 2x = 2

6 0
3 years ago
Read 2 more answers
Compare the values 4x107 is what times as much as 4x103
dezoksy [38]

Answer:

10^{4}

Step-by-step explanation:

4 x 10^7 is 40000000

4 x 10^3 is 4000

We are told that 4x10^7 is something times as much as 4x10^3

So we will work backwards to find the answer,

If you divide 40000000 by 4000 you will get 10000

10000 is the same as 10^4

7 0
2 years ago
Read 2 more answers
Suppose we are testing people to see if the rate of use of seat belts has changed from a previous value of 88%. Suppose that in
Andreas93 [3]

Answer:

a) We would expect to see 500*0.88=440

b) z=\frac{0.9 -0.88}{\sqrt{\frac{0.88(1-0.88)}{500}}}=1.376  

p_v =2*P(Z>1.376)=0.167  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion is not significant different from 0.9.

The p value is a criterion to decide if we reject or not the null hypothesis, when p_v we reject the null hypothesis in other case we FAIL to reject the null hypothesis. And represent the "probability of obtaining the observed results of a test, assuming that the null hypothesis is correct".  

Step-by-step explanation:

Data given and notation

n=500 represent the random sample taken

X=450 represent the people that have the seat belt fastened

\hat p=\frac{450}{500}=0.9 estimated proportion of people that have the seat belt fastened

p_o=0.88 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v{/tex} represent the p value (variable of interest)  Part aWe would expect to see 500*0.88=440Part bConcepts and formulas to use  We need to conduct a hypothesis in order to test the claim that the true proportion changes fro m 0.88.:  Null hypothesis:[tex]p=0.88  

Alternative hypothesis:p \neq 0.88  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.9 -0.88}{\sqrt{\frac{0.88(1-0.88)}{500}}}=1.376  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z>1.376)=0.167  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion is not significant different from 0.9.

The p value is a criterion to decide if we reject or not the null hypothesis, when p_v we reject the null hypothesis in other case we FAIL to reject the null hypothesis. And represent the "probability of obtaining the observed results of a test, assuming that the null hypothesis is correct".  

8 0
3 years ago
A walk-in medical clinic believes that arrivals are uniformly distributed over weekdays (Monday through Friday). It has collecte
allsm [11]

Answer:

The degrees of freedom are given by;

df =n-1= 5-1=4

The significance level is 0.1 so then the critical value would be given by:

F_{cric}= 7.779

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

Step-by-step explanation:

For this case we have the following observed values:

Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100

For this case the expected values for each day are assumed:

E_i = \frac{100}{5}= 20

The statsitic would be given by:

\chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}

Where O represent the observed values and E the expected values

The degrees of freedom are given by;

df =n-1= 5-1=4

The significance level is 0.1 so then the critical value would be given by:

F_{cric}= 7.779

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

5 0
3 years ago
If f(x)=x^2-7 and h(x)=7x-5, then f(h(2))=
zaharov [31]
We are given 3 equations. Using these equations we can find f(h(2)).

h(x)=7x-5
h(2)=7(2)-5
h(2)=14-5
h(2)=9

f(x)=x^2-7
f(h(2))=(7x-5)^2-7
we know the answer for h(2) by now, so we can substitute for that.
f(9)=9^2-7
f(9)=81-7
f(9)=74

so f(h(2))=74
5 0
3 years ago
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