All categories

3 years ago

Anusha is walking on a hiking trail at a rate of 3/4 miles in 1/4 hour. At this rate, how far will Anusha walk in an hour?

2 answers:

4 0

At this rate, Anusha will walk 3 miles in an hour. You can find this in two ways, the first being simply multiplying the 3/4 by 4 because it is 1/4 of the destination time. You can also do 3/4 mile over 15 minutes and a variable of your choice over 60 minutes and cross multiply to get 15a=45. Next, divide 45 by 15 and you get "3," meaning 3 miles were traveled.

kherson [118]3 years ago

3 0

3 miles. Using cross-multiplication, 3×4 = 12 and 4×1 = 4, so 12/4 = 3.

You might be interested in

Its really hard !!!!!!!!!!!!!!!

Tomtit [17]

Answer:

B) 65%

Step-by-step explanation:

4 0

3 years ago

PLEASE HELPPPPP

-Dominant- [34]

Answer:

126

Step-by-step explanation:

1200x.021=25.20 interest per year

25.20 x 5 years = 126

assumes no compounding

6 0

3 years ago

Please help me. Its an escape room

Anna35 [415]

Answer:

Dud there are directions go to the mission Page

3 0

3 years ago

Matt can walk 500 m from his home on King Street, and then 900m along Queen Street to go to his school. He can also walk across

brilliants [131]

Answer:

He walks 1030 meters if he walks across the park.

Step-by-step explanation:

In order to solve this question we will need to know that $c^{2} = a^{2} + b^{2}$ (were c is the length of the hypotenuse (the diagonal line) of a right angle triangle, and a and b are the legs (the sides that form a right angle). So them means that.....

Let "c" be the distance he will need to walk if he was going to go through the park

Let "a" be the distance he walks on King Street

Let "b " be the distance he walks on Queen Street, then.....

$c^{2} = a^{2} + b^{2}$

$c = \sqrt{a^{2} + b^{2} }$

(Now plug in the values of a and b and get.....)

c = $\sqrt{500^{2} + 900^{2} }$

c = $\sqrt{1060000 }$

c = 1029.563014............

So I would assume that you have to round to the nearest meter. And as a result we get 1030 meter.

7 0

3 years ago

A pool measuring 20 meters by 28 meters is surrounded by a path of uniform width, as shown in the figure. If the area of the po

krok68 [10]

X= width of the path.
we can suggest this equation:

(20+2x)(28+2x)=1584

we solve this equation:
(20+2x)(28+2x)=1584
560+40x+56x+4x²=1584
4x²+96x-1024=0
4/4x²+96/4x-1024/4=0/4
x²+24x-256=0

We solve this square equation:

x=[-24⁺₋√(576+1024)]/2=(-24⁺₋40)/2
we have two solutions:
x₁=(-24-40)/2=-32 this solution is not valid.
x₂=(-24+40)/2=8

Answer: the width of the path is 8 m.

7 0

3 years ago