-6x^3y + 9x^2y^2 - 12xy^3
-3xy(2x^2) - 3xy(-3xy) - 3xy(4y^2)
-3xy(2x^2 - 3xy + 4y^2)
The answer is C.
Answer:
Step-by-step explanation:
It is assumed the question is about finding the minimum value as the given function has no maximum value, it is + ∞ as the coefficient of x² is positive
<u>The minimum/maximum value of a quadratic function is the vertex, which is at:</u>
<u>For the given function y = x² -10x + 31, the vertex is:</u>
- x = - (-10)/2*1 = 10/2 = 5
<u>The value of y at this point is:</u>
- y = 5² - 10*5 + 31 = 25 - 50 + 31 = 6
<u>The point is </u>
Amount saved= fraction saved x amount of money received
A= 1/6 x 2
A=1/3
A=.33
33 cents or $.33
Hope this helps :)
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18.55 Hope this help that will be your answer have a good day or night.