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sasho [114]
3 years ago
6

Describe the function over each part of its domain. State whether it is constant, increasing, or decreasing, and state the slope

over each part
HELP ASP

Mathematics
1 answer:
Amanda [17]3 years ago
8 0

The attached image completes the question.

Answer:

- The part (0, 12000) is constant and the slope is zero

- The part (12000, 38000) is decreasing and slope is negative 0.26.

Step-by-step explanation:

Checking the given graph, we see that

For x = 0  to x = 12,000, the values of y are unchanged. For this, we say it is constant.

The slope here is: 0.85 - 0.85 = 0

For x = 12,000  to x = 38,000, the values of y are decreasing. For this, we say it is negative.

The slope here is: 0.59 - 0.85 = -0.26.

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The half-life of the isotope Osmium-183 is 12 hours. Choose the equation below that gives the remaining mass of Osmium-183 in gr
raketka [301]

The given equations are incomprehensible, I'm afraid...

You're given that osmium-183 has a half-life of 12 hours, so for some initial mass <em>M</em>₀, the mass after 12 hours is half that:

1/2 <em>M</em>₀ = <em>M</em>₀ exp(12<em>k</em>)

for some decay constant <em>k</em>. Solve for this <em>k</em> :

1/2 = exp(12<em>k</em>)

ln(1/2) = 12<em>k</em>

<em>k</em> = 1/12 ln(1/2) = - ln(2)/12

Now for some starting mass <em>M</em>₀, the mass <em>M</em> remaining after time <em>t</em> is given by

<em>M</em> = <em>M</em>₀ exp(<em>kt </em>)

So if <em>M</em>₀ = 590 g and <em>t</em> = 36 h, plugging these into the equation with the previously determined value of <em>k</em> gives

<em>M</em> = 590 exp(36<em>k</em>) = 73.75

so 73.75 ≈ 74 g of Os-183 are left.

Alternatively, notice that the given time period of 36 hours is simply 3 times the half-life of 12 hours, so 1/2³ = 1/8 of the starting amount of Os-183 is left:

590/8 = 73.75 ≈ 74

6 0
3 years ago
Help me with this plzzzz
Firlakuza [10]

Answer:

0.25 or 1/4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The students in Suzanne's school are painting a rectangular mural outside the building that will be 15 feet by 45 feet. Scale dr
Katarina [22]

Answer:

The dimensions on paper are 1.992ft by 5.976ft with a scale factor of 7.53

Step-by-step explanation:

The first step will be to find the diagonal of the rea life mural.

We can use Pythagoras' Theorem to do this.

Diagonal = \sqrt{15^2 +45^2 } =47.43 feet.

Now we have the real-life diagonal, we will now relate the diagonal of the painting outside with the one on paper. We can do this by dividing the two diagonals.

This will be 47.43 / 6.3 units = 7.53.

The scale factor is 7.53

To get the dimensions of the length and the breadth on paper, we divide the outside dimensions by the scale factor.

This will be

Length = 15/ 7.53 = 1.992

Breadth = 45/7.53 = 5.976

Therefore, the dimensions on paper are 1.992ft by 5.976ft with a scale factor of 7.53

3 0
3 years ago
(picture included) find the area of the circle
umka21 [38]

Answer:

36πin²

Step-by-step explanation:

Area of a circle: A=\pi r^2

r - radius

We are given the diameter of the circle. The radius is half the diameter.

12/2 = 6

The radius is 6cm.

A=\pi (6)^2\\\\A=\pi 36\\\\\boxed{A=36\pi }

The area of the circle is 36πin².

Hope this helps.

8 0
3 years ago
My math teacher didn’t give us any instruction on this “quiz” I would really like if someone could help me!
algol [13]

Answer:

The first one (46.25)

Step-by-step explanation:

All you had to do was length times width.

7 0
3 years ago
Read 2 more answers
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