Yes, in a function you cannot have two different images for the same x.
Because if an x has more than one image, you couldn't tell what is the value of the image given that x.
Answer:
p(4 successes) ≈ 7.7%
Step-by-step explanation:
p(k successes in n trials) = C(n,k)·p^k·(1-p)^(n-k)
You have n=5, k=4, p=0.4, so the probability is ...
p(4 successes) = C(5,4)·(0.4)^4·(1 -0.4)^1 = 5·0.4^4·0.6 = 0.0768
p(4 successes) ≈ 7.7%
The GCF is <span>1. hope that helps</span>
-10y^2 + (-3y^2) - 4y^2 - (-6y^2) =
-10y^2 - 3y^2 - 4y^2 + 6y^2 =
-17y^2 + 6y^2 =
- 11y^2