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elena-14-01-66 [18.8K]
4 years ago
9

The perimeter of a rectangle changes from 2.5 to 10 after a dilation. What was the scale factor of the dilation?

Mathematics
2 answers:
julsineya [31]4 years ago
8 0

Answer:

B. 4

Step-by-step explanation:

Let x be the scale factor of the given dilation.

We have been given that the perimeter of a rectangle changes from 2.5 to 10 after a dilation. We are asked to find the scale factor of dilation.

The scale factor multiplied by the original side gives the length of new side after dilation, so we can set an equation as:

\text{Original length }\cdot \text{Scale factor}=\text{New length after dilation}

Upon substituting our given values in above equation we will get,

2.5\cdot x=10

Upon dividing both sides of our equation by 2.5 we will get,

\frac{2.5\cdot x}{2.5}=\frac{10}{2.5}

x=4

Therefore, the scale factor of the given dilation is 4 and option B is the correct choice.

yawa3891 [41]4 years ago
7 0
Scale factor = new length/old length

scale factor = 10/2.5 = 4

The scale factor is 4.
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3 years ago
Which exponential equation is equivalent to this logarithmic equation?
boyakko [2]

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B or A

Step-by-step explanation:

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3 years ago
In a lab, 180 cells are present at the beginning of an experiment. During the first 9 hours, the number of cells increased by 8%
jasenka [17]

Answer:

The answer is 9 hours

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4 years ago
_____ have congruent corresponding parts.
aniked [119]

Answer:

Two congruent figures

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Here we have to use the definition of congruent.

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4 0
3 years ago
JUST ANSWER PLEASE!!! QUICK
jeka57 [31]

Answer:

<u>Options 1 and 3</u>

Step-by-step explanation:

We should know that, the system of linear equations can be treated as matrices, i.e: we can modify or make any operations provide that we must apply the same operation for all terms of each equation.

Given:  the solution for the following system is (2,9)

Px + Qy = R  ⇒(1)

Tx + Uy = V  ⇒(2)

We will check which system of equation has the same solution.

<u>System A)</u>  Px + Qy = R

                  (P+T)x + (Q+U)y = R+V  ⇒(3)

So, By summing (1) and (2) we will get the equation (3)

So, system A has the same solution (2,9)

<u>System B)</u> Px + Qy = R

                 (P+2T)x + (Q+2U)y = R-2V  ⇒(4)

By multiplying equation (2) by 2 and add with equation (1), we will get:

 (P+2T)x + (Q+2U)y = R+2V

Which is not the same as equation (4)

So, system B has not the same solution (2,9)

<u>System C)</u> (T-P)x + (U-Q)y = V-R  ⇒(5)

                  Tx + Uy = V  

By multiplying equation (1) by -1 and add with equation (2), we will get the equation (5)

So, system C has the same solution of (2,9)

<u>System D)</u> (T-P)x + (Q+U)y = V-R  ⇒(6)

                  Tx + Uy = V  

We cannot get equation (6) by the same operation over equation (1)

Note the coefficient of x and y⇒ (T-P) and (Q+U)

They must be (T+P) and (Q+U) <u>OR </u>(T-P) and (Q-U)

So, system D has not the same solution of (2,9)

<u>System E)</u> (5T-P)x + (5U-Q)y = V-5R ⇒ (6)

                  Tx + Uy = V  

By subtract equation (1) from 5 times equation (2), we will get:

(5T-P)x + (5U-Q)y = 5V-R

Which is not the same as equation (6)

So, system E has not the same solution (2,9)

As a conclusion, the systems which have the same solution are:

<u>Options 1 and 3</u>

5 0
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