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3 years ago

Can you please solve?-5 (-5-3k)-5 (1-6k)

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

6 0

-5(-5-3k)-5*(1-6k)
(25-15k)-(5-30K)
30+ 15K

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A circle has a diameter of 40 in. Find the circumference of the circle to the nearest tenth. Use 3.14 for pi .

Lesechka [4]

Answer:

126 inches

Step-by-step explanation:

C = 2π·r = π·d = 3.14×40in = 125.6 inches ≈ 126 inches

6 0

3 years ago

A 95% confidence interval for a population mean is computed from a sample of size 400. Another 95% confidence interval will be c

Anna [14]

Answer:

The interval from the sample of size 400 will be approximately One -half as wide as the interval from the sample of size 100

Step-by-step explanation:

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the 95% confidence interval is dependent on the value of the margin of error at a constant sample mean or sample proportion

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

Here assume that $Z_{\frac{\alpha }{2} } \ and \ \sigma \$ is constant so

$E = \frac{k}{\sqrt{n} }$

=> $E \sqrt{n} = K$

=> $E_1 \sqrt{n}_1 = E_2 \sqrt{n}_2$

So let $n_1 = 400$ and $n_2 = 100$

=> $E_1 \sqrt{400} = E_2 \sqrt{100}$

=> $E_1 = \frac{\sqrt{100} }{\sqrt{400} } E_2$

=> $E_1 = \frac{1}{2 } E_2$

So From this we see that the confidence interval for a sample size of 400 will be half that with a sample size of 100

7 0

2 years ago

What’s the are of a trapezoid

kozerog [31]

I need to know the question that tells us what the other parts are.

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3 years ago

The sum of a student's three score is 246. if the first is 14 points more than the second, and the sum of the first two is 6 mor

mr_godi [17]

Let the second score = x
⇒ second score = x

the first is 14 points more than the second
⇒ first score = x + 14

the sum of the first two is 6 more than twice the third
⇒ third score = 1/2 (x + x + 14 - 6) = x + 4

The sum of a student's three score is 246
⇒ x + (x + 14) + (x + 4) = 246

Solve x:
x + x + 14 + x + 4 = 246
3x + 18 = 246
3x = 228
x = 76

second score = x = 76
first score = x + 14 = 76 + 14 = 90

Answer: 90

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3 years ago

What number should go in box A on this number line? 4. 5. A

cestrela7 [59]

Answer:

Step-by-step explanation:

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2 years ago