Step-by-step explanation:
1)The given equations are:
x − 2y = 6 ...(i)
3x − 6y = 0 ...(ii)
Putting x = 0 in equation (i) we get
=> 0 - 2y = 6
=> y = -3
x = 0, y = -3
Putting y = 0 in equation (i) we get
⇒x-2×0=6
⇒x=6
x = 6, y = 0
Use the following table to draw the graph
x 0 6
y -3 0
Plotting the two points A(0, -3) and B(6,0) equaion (1) can be drawn
Graph of the equation ..(ii)
3x - 6y = 0 ...(ii)
Putting x = 0 in equation (ii) we get
⇒3×0-6y=0
=> y = 0
x = 0, y = 0
Putting x = 2 in equation (2) we get
⇒3×2-6y=0
=> y = 1
x = 2, y = 1
Use the following table to draw the graph.
x 0 2
y 0 1
Draw the graph by plotting the two points O(0,0) and D(2,1) from table
We see that the two lines are parallel, so they won’t intersect
Hence there is no solution
2)
Answer:
Step-by-step explanation:
someone pls answer my new question thanks
The degree of the polynomial will tell you the max amount of zeros you will have. 11 in this case.
However you can also have 9,7,5,3,1 (keep subtracting by 2)
So the answer is 1.
I believe the answer to your question would be x = -y + 2
Answer:
No
Step-by-step explanation:
