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Agata [3.3K]
3 years ago
5

PLEASE HELP!!!!!!!------- Ann sells boxes of cookies for $10 each. Abdul sells boxes of cookies for $8 each. Each of them sold t

he same dollar amount. It was the smallest dollar amount which this was possible.​
Mathematics
1 answer:
madreJ [45]3 years ago
6 0

Answer:

They both sold $40 worth of cookies.

Step-by-step explanation:

Using multiples the first multiple that 10 and 8 have in common is 40.

10,20,30,40

8,16,24,32,40

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For Sunday's brunch, Alexis is making a recipe that requires 8 cups of milk. She has 3 quarts of milk. Does she have enough for
babunello [35]

Answer:

yes

Step-by-step explanation:

she needs 8 cups and 3 quarts is 12 cups

3 0
3 years ago
I will brainliest if you sub and stay subbed to JD Outdoors & Gaming​
slava [35]

Answer:

sure why not

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
VN
navik [9.2K]

Answer:

£2,121.8

Step-by-step explanation:

Given the following;

Principal P = £2000

Rate r = 3%

Time t = 2 years

n = 1 (time of compounding)

Using the compound interest formula;

A = P(1+r)^t

A = 2000(1+0.03)^2

A = 2000(1.03)^2

A = 2000(1.0609)

A = 2,121.8

hence the amount that will be in his account after 2 years is £2,121.8

6 0
3 years ago
If θ is an angle in standard position that terminates in Quadrant III such that tanθ = 5/12, then sinθ/2 = _____
babunello [35]

Answer:

sin θ/2=5√26/26=0.196

Step-by-step explanation:

θ ∈(π,3π/2)

such that

θ/2 ∈(π/2,3π/4)

As a result,

0<sin θ/2<1, and

-1<cos θ/2<0

tan θ/2=sin  θ/2/cos θ/2

such that

tan θ/2<0

Let

t=tan θ/2

t<0

By the double angle identity for tangents

2 tan θ/2/1-(tanθ /2)^2  = tanθ

2t/1-t^2=5/12

24t=5 - 5t^2

Solve this quadratic equation for t :

t1=1/5 and

t2= -5

Discard t1 because t is not smaller than 0

Let s= sin θ/2

0<s<1.

By the definition of tangents.

tan θ/2= sin θ/2/ cos θ/2

Apply the Pythagorean Algorithm to express the cosine of θ/2 in terms of s. Note the cos θ/2 is expected to be smaller than zero.

cos θ/2 = -√1-(sin θ/2)^2 = - √1-s^2

Solve for s.

s/-√1-s^2 = -5

s^2=25(1-s^2)

s=√25/26 = 5√26/26

Therefore

sin θ/2=5√26/26=0.196....

7 0
3 years ago
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- 2x - 1 = {3}^{( - x)}

and 2^(-x) + 2 = -5^x + 3

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