Explain how you change a decimal to a fraction.

Mathematics

2 answers:

maw [93]2 years ago

7 0

Answer:

Decimals can be written in fraction form. To convert a decimal to a fraction, place the decimal number over its place value. For example, in 0.6, the six is in the tenths place, so we place 6 over 10 to create the equivalent fraction, 6/10. If needed, simplify the fraction.

andre [41]2 years ago

7 0

Answer:

Decimals can be written in Fractions form. To convert a decimal to a fraction, place the decimal number over its place value . For example, in 0.6 the six is in the tenths place so we place 6 over 10 to create the equivalent fraction 6/10 if needed simplify the fraction

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Aleks04 [339]

Answer: 40%

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Work Shown:

"given that it's a senior" is an important piece of info that tells us to only focus on the "seniors" column. The word "given" is an indication that we know this information 100%

There are 5 seniors (2+3 = 5) and 2 of them are male. So 2/5 = 0.40 = 40% of the seniors are male. The probability of selecting a male, if we know this person is a senior, is 40%

3 0

2 years ago

Read 2 more answers

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larisa [96]

Answer:

-2, 8/3

Step-by-step explanation:

You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...

A = (1/2)(f(a) +f(4))(4 -a)

= (1/2)((3a -1) +(3·4 -1))(4 -a)

= (1/2)(3a +10)(4 -a)

We want this area to be 12, so we can substitute that value for A and solve for "a".

12 = (1/2)(3a +10)(4 -a)

24 = (3a +10)(4 -a) = -3a² +2a +40

3a² -2a -16 = 0 . . . . . . subtract the right side

(3a -8)(a +2) = 0 . . . . . factor

Values of "a" that make these factors zero are ...

a = 8/3, a = -2

The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.

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<em>Alternate solution</em>

The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.