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ehidna [41]
3 years ago
10

If a foosball table is 3cm longer then twice the width. Write a simplified expression for the area of the foosball table

Mathematics
1 answer:
djverab [1.8K]3 years ago
5 0
Your expression is A = (L + 3) x (2w) x h
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Order the numbers from greatest to least 39,008; 39,801; 37,999
bearhunter [10]
37,999. 39,008,. 39,801
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3 years ago
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Can you please explain to me how I would solve this problem? Can you please explain/and show all the steps?
Lena [83]
22 = z + (-9) Switch the sides
z = 22 - (-9) Solve
z = 31 So, z = 31
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3 years ago
What is the difference? StartFraction x 5 Over x 2 EndFraction minus StartFraction x 1 Over x squared 2 x EndFraction StartFract
Troyanec [42]

The difference of the given fraction is expressed as \frac{x^2+4x-1}{x(x+2)}

Given the expression:

  • \frac{x+5}{x+2}-\frac{x+1}{x^2+2x} \\

Take the LCM of the fraction to have:

=\frac{x+5}{x+2}-\frac{x+1}{x(x+2)} \\=\frac{x(x+5)-(x+1)}{x(x+2)} \\=\frac{x^2+5x-x-1}{x(x+2)}\\=\frac{x^2+4x-1}{x(x+2)}

Hence the difference of the given fraction is expressed as \frac{x^2+4x-1}{x(x+2)}

Learn more on fractions here; brainly.com/question/78672

7 0
2 years ago
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Steve Rogers invested $2400 in an account tht pays 4% compounded continuously and how has $3500. How long did it take Steve's mo
Sedbober [7]

Answer:20years

Step-by-step explanation:

6 0
2 years ago
Urn 1 contains 3 blue tokens and 2 red tokens; urn 2 contains 2 blue tokens and 4 red tokens. All tokens are indistinguishable.
Dmitry_Shevchenko [17]

Answer:

RR = 0.4

RB = 0.3

BB = 0.22

BR = 0.30

Step-by-step explanation:

P( Urn 1 ) = 2/6 = 1/3

P( Urn 2 ) = 1 - 1/3 = 2/3

Urn 1 contains : 3 blue and 2 red

P( blue | urn 1 ) = 3/5 ( with replacement ) , P( blue | urn 1 ) = 3/4 ( without replacement )

P( red | urn 1 ) = 2 / 5 ( with replacement ) , P(red | urn 1 ) = 1/2 ( without replacement )

Urn 2 contains : 2 blue and 4 red

P ( blue | urn 2 ) = 1/3 ( with replacement ) , P( blue | urn 2 ) = 2/5 ( without replacement )

P ( red | urn 2 ) = 2/3 ( with replacement) , P( red | urn 2 ) = 4/5 ( without replacement )

Determine

<u>i) Possible outcomes when two tokens are drawn from either Urn without replacement </u>

RR = [[ ( 2/5 * 1/3 ) + ( 2/3 * 2/3 ) ] * [( 1/2 * 1/3 ) + ( 4/5 * 2/3 ) ]] = 0.4

RB = [[ (2/5 * 1/3 ) + ( 2/3 * 2/3 ) ] * [ ( 3/4 *1/3 ) + ( 2/5 * 2/3 ) ]] ≈ 0.3

BB = [[ ( 3/5 * 1/3 ) + ( 1/3 * 2/3 ) ] * [ ( 3/4 *1/3 ) + ( 2/5 * 2/3 ) ]] ≈ 0.22

BR = [[ ( 3/5 * 1/3 ) + ( 1/3 * 2/3 ) ] * [ ( 1/2 * 1/3 ) + ( 4/5 * 2/3 ) ]] ≈ 0.30

<u />

8 0
3 years ago
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