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marin [14]
3 years ago
11

Let (-3,5) be a point on the terminal side of theta. Find the exact values of sin theta, secant theta, and tangent theta

Mathematics
1 answer:
bagirrra123 [75]3 years ago
8 0

Answer:

Cosθ = 0.5145

Sinθ = 0.8575

Secθ = 1.9436

tanθ = 1.667

Step-by-step explanation:

From the figure attached,

Point P(-3, 5) is on the terminal side and AB is the initial side of the angle PAB.

If m∠PAB = θ

AB = \sqrt{(3)^{2}+(5)^{2}}

     = \sqrt{34}

     = 5.831

Then Cosθ = \frac{AB}{AP} = \frac{3}{5.831}

Cosθ = 0.5145

Sinθ = \frac{PB}{AP}

Sinθ = \frac{5}{5.831}

Sinθ = 0.8575

Secθ = \frac{1}{\text{Cos}\theta}

Secθ = \frac{1}{0.5145}

Secθ = 1.944

tanθ = \frac{PB}{AB}

tanθ = \frac{5}{3}

tanθ = 1.667

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The question is incomplete.

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