Answer:
Triangle- (height × base)/2
Rhombus-(First diagonal×Second diagonal)/2
Trapezoid- (First base+second base)/2×height
N-gon= (Side-2)*180
The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
Learn more on polynomial here: brainly.com/question/2833285
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(GCF), 'y'. y(12xy + 4x2<span> + 9y</span>2<span>)
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Answer:
its blurry
Step-by-step explanation:
(-2-5)^2+(1--5)^2
49+36
Sq rt of 85= 9.2