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cupoosta [38]
3 years ago
11

Pls help!! will give brainliest, thx, and 5star

Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0

Answer:

178

Step-by-step explanation:

The area of the rectangle is 6x25=150.

The area of the two semicircles on the sides is equal to the area of one circle with a radius of 3, so the area is 3\pi ^{2} which is approximately 28.27.

150+28.27=178.27

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Which ordered pair is the solution to the system of equations?
brilliants [131]
X+y=-1
3x-y=21
add them equations

x+y=-1
<u>3x-y=21 +</u>
4x+0y=20

4x=20
divide by 4
x=5

x+y=-1
5+y=-1
minus 5 both sides
y=-6

(x,y)
(5,-6)

D is answer
3 0
3 years ago
PLEASE HELP ME!!PLEASE HELP ME!!!!!
muminat

Answer:

The actual dimensions would be 3.375 feet by 3.5 feet. The area of the room would be 11.8 square feet.

Step-by-step explanation:

5 0
2 years ago
In a binomial experiment with 45 trials, the probability of more than 25 success can be approximated by What is the probability
Pani-rosa [81]

Answer:

0.6 is the probability of success of a single trial of the experiment

Complete Problem Statement:

In a binomial experiment with 45 trials, the probability of more than 25 successes can be approximated by P(Z>\frac{(25-27)}{3.29})

What is the probability of success of a single trial of this experiment?

Options:

  • 0.07
  • 0.56
  • 0.79
  • 0.6

Step-by-step explanation:

So to solve this, we need to use the binomial distribution. When using an approximation of a binomially distributed variable through normal distribution , we get:

\mu =\frac{np}{\sigma}=\sqrt{np(1-p)}

now,

Z=\frac{X-\mu}{\sigma}

so,

by comparing with P(Z>\frac{(25-27)}{3.29}), we get:

μ=np=27

\sigma=\sqrt{np(1-p)} =3.29

put np=27

we get:

\sigma=\sqrt{27(1-p)} =3.29

take square on both sides:

10.8241=27-27p

27p=27-10.8241

p=0.6

Which is the probability of success of a single trial of the experiment

5 0
3 years ago
What is 2+2 equals to ??
romanna [79]

Answer: 4

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
HELP I WILL GIVE 5 POINTS TO WHOM EVER CAN ANSWER THESE LAST 2 QUESTIONS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
vodka [1.7K]
Group and factor
undistribute then undistribute again
remember
ab+ac=a(b+c)
this is important



6d^4+4d^3-6d^2-4d
undistribute 2d
2d(3d^3+2d^2-3d-2)
group insides
2d[(3d^3+2d^2)+(-3d-2)]
undistribute
2d[(d^2)(3d+2)+(-1)(3d+2)]
undistribute the (3d+2) part
(2d)(d^2-1)(3d+2)
factor that difference of  2 perfect squares
(2d)(d-1)(d+1)(3d+2)






77.
group
(45z^3+20z^2)+(9z+4)
factor
(5z^2)(9z+4)+(1)(9z+4)
undistribuet (9z+4)
(5z^2+1)(9z+4)
7 0
3 years ago
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