Question

Find the area of rectangle ABCD. 20 10 √2+ √82 24 12

Answer 1

Answer:

12 units²

Step-by-step explanation:

AB = $\sqrt{(x_{2} -x_{1})^2 +(y_{2} -y_{1})^2 }$ = $\sqrt{(0-3)^2 +(0-3)^2}$ = 3√2

BC = $\sqrt{(5-3)^2 +(1-3)^2}$ = 2√2

$A_{ABCD}$ = AB × BC = 3√2 × 2√2 = 12 units²

Answer 2

Answer:

So I did the assignment, and the answer that you're looking for in this problem would be 12.