On 2 the equation will be 5,750-500x when you graph that on the y-axis put go up 5,750 and over 0 from tag point go down 500 and to the right 1.. And on b it will be 3,500-250x on the y-axis go up 3,500 and over 0 from that point go down 250 and over to the right 1..
Answer: (x^2)/25 + (16y^2)/375) = 1
Step-by-step explanation:
since foci are symetrically located on x-axis about origin, the equation of the ellipse must be of the following form:
(x^2)/(a^2) + (y^2)/(b^2) = 1, where a = semi-major axis, and b = semi-minor axis,
and: e = eccentricity = sqrt(a^2 - b^2)/a = 0.25; foci located at (+/- sqrt(a^2 - b^2),0) = (+/- 1.25,0)
---> sqrt(a^2 - b^2) = 1.25 ---> 1.25/a = 0.25 ---> a = 1.25/0.25 ---> a = 5; and sqrt(a^2 - b^2) = 1.25 = 5/4
---> a^2 - b^2 = (5/4)^2 = 25/16; or 5^2 - b^2 = 25/16 ---> 25 - b^2 = 25/16;
---> b^2 = 25 - (25/16) = 25[1 - 1/16] = 25(15)/16 = 375/16
---> (x^2)/25 + (y^2)/(375/16) = 1 ---> (x^2)/25 + (16y^2)/375) = 1
Hope this help...and correct it's been awhile..Let me know
Answer:
7 seconds
Step-by-step explanation:
Hello There!
I had created a graph to make it easier to understand
So when y = 0 is when the ball is at the ground
when y = 0 x = 7 so it took about 7 seconds for the ball to hit the ground
That would be 423 total. :)
