A rational expression is defined for all real numbers except the zeros of the denominator.
Then, find the zeros of the denominator to find the values for which the given rational expression is undefined:
Use quadratic formula:
![\begin{gathered} ax^2+bx+c=0 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20ax%5E2%2Bbx%2Bc%3D0%20%5C%5C%20x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D%20%5Cend%7Bgathered%7D)
![\begin{gathered} n=\frac{-76\pm\sqrt[]{76^2-4(84)(16)}}{2(84)} \\ \\ n=\frac{-76\pm\sqrt[]{5776-5376}}{168} \\ \\ n=\frac{-76\pm\sqrt[]{400}}{168} \\ \\ n=\frac{-76\pm20}{168} \\ \\ n_1=\frac{-76+20}{168}=\frac{-56}{168}=-\frac{1}{3} \\ \\ n_2=\frac{-76-20}{168}=\frac{-96}{168}=-\frac{4}{7} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20n%3D%5Cfrac%7B-76%5Cpm%5Csqrt%5B%5D%7B76%5E2-4%2884%29%2816%29%7D%7D%7B2%2884%29%7D%20%5C%5C%20%20%5C%5C%20n%3D%5Cfrac%7B-76%5Cpm%5Csqrt%5B%5D%7B5776-5376%7D%7D%7B168%7D%20%5C%5C%20%20%5C%5C%20n%3D%5Cfrac%7B-76%5Cpm%5Csqrt%5B%5D%7B400%7D%7D%7B168%7D%20%5C%5C%20%20%5C%5C%20n%3D%5Cfrac%7B-76%5Cpm20%7D%7B168%7D%20%5C%5C%20%20%5C%5C%20n_1%3D%5Cfrac%7B-76%2B20%7D%7B168%7D%3D%5Cfrac%7B-56%7D%7B168%7D%3D-%5Cfrac%7B1%7D%7B3%7D%20%5C%5C%20%20%5C%5C%20n_2%3D%5Cfrac%7B-76-20%7D%7B168%7D%3D%5Cfrac%7B-96%7D%7B168%7D%3D-%5Cfrac%7B4%7D%7B7%7D%20%5Cend%7Bgathered%7D)
<h2>Then, the given rational expression is undefined for:</h2><h2>n= -1/3 , -4/7</h2>
I think you do
5c=120
5c/5 120/5 =24
you need to get c by itself so divide 5 . When you divide 5 by one side do it to the other
120/5=24
3. Answer 24
Answer:
= $90
Step-by-step explanation:
I = prt
I = 500 x 0.06 x 3
I = $90
$300 in saving account that earn 5%
5/100 x 12=3/5 =0.6
300+0.6=$300.6
3.006%
3.006% in one year
Answer:
2/5
Step-by-step explanation:
add 2+3 (denominators) and 1+1 (numerators)
