Answer to question four is B
Answer:
If tan A = 3 / 5, then sin A = 3√34 / 34 and cos A = 5√34 / 34 .
Assuming x = 5 and y = 3 (The problem is deficient in this regard)
5(3√34 / 34) + 3(5√34 / 34)
30√34 / 34
15√34 / 17
Explanation:
I hope this helps!
<span>An elliptical galaxy has stars symmetrically dispersed in a spherical or flattened shape.</span>
