Question

A line passes through the point (–3, –4) and its y-intercept is (0, –9). What is the equation of the line that is parallel to the first line and passes through the point (3, –7)?

Answer 1

Find the slope of this line
slope=(y2-y1)/(x2-x1)
slope=(-9-(-4))/(0-(-3))=(-9+4)/(3)=-5/3

yint is y=-9
y=mx+b
y=-5/3x-9

parllell means has same slope

y=-5/3x+b
find b by inputing point
(3,-7)
(x,y)
x=3
y=-7
-7=-5/3(3)+b
-7=-5+b
add 5
-2=b

the equation of the line is y=-5/3x-2