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raketka [301]
3 years ago
15

Suppose the first five terms of a sequence are 4, 5, 9, 27, 123. How could the next term in the sequence be generated?

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0
The <u>correct answer</u> is:

B) by finding the factorial of the term number, then adding 3 to the result.

Explanation:

If we add 3 before finding the factorial, for the first term we would have:

(1+3)! = 4! = 4*3*2*1 = 24.  

This is not the first term, so this is not accurate.

Finding the factorial of the term number and then adding 3, we would have:
1!+3 = 1+3 = 4
2!+3 = 2*1+3 = 2+3 = 5
3!+3 = 3*2*1+3 = 6+3 = 9
4!+3 = 4*3*2*1+3 = 24+3 = 27
5!+3 = 5*4*3*2*1+3 = 120+3 = 123

This is the correct answer.
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Hope this helps!
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3 years ago
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(x-4)/5=9-(2x-41)/9
jok3333 [9.3K]
For this question, you have to take Least Common Multiplier for which in this case will be "45" as, the denominators can get similar and get multiplied by a same value to form a similar expression. This allows us to cancel out them by common factors. Full process shown below.

\mathbf{Given \: \: Expression: \: \dfrac{x - 4}{5} = 9 - \dfrac{2x - 41}{9}}

\mathbf{\dfrac{x - 4}{5} \times 45 = 9 \times 45 - \dfrac{2x - 41}{9} \times 45}

\mathbf{9(x - 4) = 405 - 5 (2x - 41)}

\mathbf{9x - 36 = 405 - 10x + 205}

\mathbf{9x - 36 = - 10x + 610}

\mathbf{9x - 36 + 36 = - 10x + 610 + 36}

\mathbf{9x = - 10x + 646}

\mathbf{9x + 10x = - 10x + 646 + 10x}

\mathbf{19x = 646}

\mathbf{\dfrac{19x}{19} = \dfrac{646}{19}}

\mathbf{\therefore \quad x = 34}

\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is; \: \: x = 34}}}

Hope it helps.
3 0
2 years ago
HELP
Debora [2.8K]

Answer:

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Ella has only quarters and nickels in her wallet. She has 2 more quarters than nickels. The total value of the coins is $2.00
aleksley [76]
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Step-by-step explanation:

Look at the picture

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